First picture)
I: 5x+2y=-4
II: -3x+2y=12
add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2
insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3
(-2,3)
question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs
insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults
insert adults into II:
33-8=childs
25=childs
so it's the last option
question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6
so it's the last option
question 8)
I: x+y=12
II: x-y=6
subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3
insert y into I:
x+3=12
x=9
(9,3)
question 9)
I: x+y=6
II: x=y+5
if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6
which is the second option :)
Answer:
(-5,1)
Step-by-step explanation:
Add it together
3x - 2x = x
y - y = 0
9 - 14 = -5
x = -5
Choose a random equation, doesn't matter.
3x + y = -14
3(-5) + y = -14
-15 + y = -14
y = -14 + 15
y = 1
Let
be the volume of 20% solution,
the volume of the 60% solution. We want a total volume of 400 mL in the final mixture, so

Each mL of either solution will contribute a corresponding concentration, and in the final mixture we want the 400 mL to have a 40% concentration, which means we should also have

Solve the system and we get
.
Answer: Circle
Solve for area
A≈86.66in²
C Circumference
Using the formulas
A=πr2
C=2πr
Solving forA
A=C2
4π=332
4·π≈86.65987in²
Step-by-step explanation: