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Molodets [167]
3 years ago
5

Use the discriminant to determine the number of solutions and types of solutions for the quadratic equation, below. Then answer

the questions in the box. (4 points) x^2+ 8x = 13
A. Discriminant = _______________
B. Number of solutions for the quadratic equation = ________
C. Type of solutions (circle one): Real /Imaginary
D. Type of solutions (circle one): Rational/irrational
Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

A. Discriminant = 116

B. Number of solutions for the quadratic equation = 2

C. Type of solutions (circle one):Imaginary

D. Type of solutions (circle one):irrational

Step-by-step explanation:

The given quadratic equation is

{x}^{2}  + 8x = 13

We rewrite in standard form to get;

{x}^{2}  + 8x   - 13 = 0

The discriminant is

D =  {b}^{2}  - 4ac

where a=1, b=8, c=-13

We substitute to get:

D =  {8}^{2}  - 4 \times 1 \times  - 13

D = 64  + 52

D = 116

Since the discriminant is great than zero, we have two distinct real roots

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Answer:

A:90

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3 years ago
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adell [148]

The correct option is (B) show that Mrs. Deverell continues to be diminished in her new home.

<h3>What does line 73 described?</h3>

In line 73, the author compares Mrs. Deverell to an "intimidated child" primarily in order to -

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5 0
1 year ago
For questions 1 and 2, use factoring to find the x-intercepts of these quadratic equations.
Marysya12 [62]
1.x^2 +6x - 4 = 6x
X^2 + 6x -4 - 6x = 0
X^2 - 4 = 0
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X^2 - 4 = 0 can be written as (x-2) (x+2) = 0
(X-2)=0 therefore x= 2

(X+2)=0 therefore x= -2

2. X^2 - 8x = -6x
X^2 -8x + 6x = 0
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2 years ago
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3 years ago
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