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stira [4]
2 years ago
11

2) There are 40 boys and 60 girls in a class of students. What is the ratio of girls to students

Mathematics
2 answers:
ra1l [238]2 years ago
8 0

Answer:

60:100, 6/10, 3/5, 6 to 10, etc.

Step-by-step explanation:

You take the number of girls over total students which is boys + girls. Since there's 40 boys and 60 girls, it's 60 girls to 100 students which can be written in several ways.

Vikki [24]2 years ago
5 0

Answer:

60:100 / 3:5

Step-by-step explanation:

You first add the total number of students which is (40boys + 60girls) which gives us 100 students.

Then arrange the ratio of girls to students as per the question that is 60:100, reduce it to its lowest term that is dividing the ratio by 20, and finally got 3:5

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24hours divided by 2 is 12

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A culture of bacteria has an initial population of 650 bacteria and doubles every 9 hours. Using the formula Pt=P0⋅2tdP_t = P_0\
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So is doubling, first off, meaning, if the current amount say P, then when it doubles is 2P, or double that, or P + P, so the rate of growth is 100%, since it's doubling.

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\bf \textit{Periodic/Cyclical Exponential Growth}\\\\
A=P(1 + r)^{\frac{t}{c}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &650\\
r=rate\to 100\%\to \frac{100}{100}\to &1.00\\
t=\textit{elapsed time}\to &10\\
c=period\to &9
\end{cases}
\\\\\\
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2 years ago
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Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1, show that their volumes are in
Nuetrik [128]
<h2>\large\bold{\underline{\underline{Question:-}}}</h2>

Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1 show that their volumes are in the ratio 3 : 1.

<h2>\large\bold{\underline{\underline{Solution:-}}}</h2>

⇒ Ratio of heights of two cones = 1 : 3

⇒ Ratio of radius of their bases = 3 : 1

⇒ We know that V = 1/3πr²h

⇒ Ratio of their volume = V1 : V2

\underline{ \underline{ \sf{Let's \:  find  \: the  \: ratio  \: of \:  their  \: volumes:}}}

{ \implies{ \sf  {V _{1}  :  V_{2}}}}

{ \implies{ \sf{ \frac{1}{3} \pi \:  { r_{1}}^{2}  h_{1} :  \frac{1}{3}  \pi \:  { r_{2} }^{2}  h_{2}}}}

{ \implies{ \sf{ {r_{1}}^{2}  h_{1} :  { r_{2}}^{2} h_{2}}}}

{ \implies{ \sf{ \frac{ { r_{1} }^{2} }{ { r_{2} }^{2} }  :  \frac{ h_{2} }{ h_{1} } }}} \\

{ \implies{ \sf{ \frac{ {3}^{2} }{ {1}^{2} }  :  \frac{3}{1} }}} \\

{ \implies{ \sf{ \frac{9}{1} :  \frac{3}{1}  }}} \\

{ \implies{ \sf{3 : 1}}} \\

{ \therefore{ \sf{ \green{Ratio  \: of  \: their \:  volumes = 3 : 1}}}}

4 0
3 years ago
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