Can someone please help with the above question thank you

Sonbull [250]

1) this is total area of two triangle
area of a triangle=1/2*b*h
A=1/2*9*4
A=18 inches^2
multiply by 2 because there are two triangle with same measure
2A=2*18=36 inches^2

3) this is a area of rectangle and a triangle and then subtract
A2=9.3x7.8= 72.54
area of triangle A1=1/2*7.8 *3.3=12.87
A2-A1=59.69 mm^2

5) now u ca do it

4 0

3 years ago

What is the answer to this problem 1/2=q 2/3?

Angelina_Jolie [31]

3/2 = 2q
q = 3/2 ÷ 2
q = 3/2 × 1/2
q = 3/4

6 0

3 years ago

I Need Help Pwease :-><br> ******************************

MissTica

Answer:

Area: 135 ft^2

Perimeter: 50 ft

Step-by-step explanation:

area:

take the rectanle so length 12 x 9 = 108 so that is the length of the rectangle and now we need to find that of the triangle left over

subract 18 - 12 = 6 so that is the base of the trianle and we know the side length is 9 so plus it in A = (9)(6)/2

A = 54/2

A = 27

add 27 + 108 to get the total area

135

perimeter:

18 + 9 + 11 + 12 = 50

5 0

3 years ago

Read 2 more answers

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow

Mrrafil [7]

Answer:

$\displaystyle \frac{54}{5405}$ .

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

$\displaystyle \left(50\atop 5\right) = 2,118,760$ .

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

$\displaystyle \left( 28\atop 2\right) = 378$ .

Number of ways to choose 3 green candies out of a batch of 8:

$\displaystyle \left(8\atop 3\right)=56$ .

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

$\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168$ .

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

$\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}$ .

3 0

3 years ago

The table shows the linear relationship between the average height in feet of trees on a tree farm and the number of years till

siniylev [52]

Step-by-step explanation:

the equation :

Hn = 7n + 3

where :

Hn : the height of trees at year to-n

n : year to-n (n = 1,2,3,...)

so, the rate of change : increasing 7 feet per year.

8 0

3 years ago