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3 years ago

Given that the f(y) = y - 1 and g(y) = y^3 - 2y - 1, find (gof) (y)I and hence, (gof) (-6).

1 answer:

3 0

$(g \circ f)(y)=(y-1)^3-2(y-1)-1\\(g \circ f)(y)=y^3 - 3 y^2 + 3 y - 1-2y+2-1\\(g \circ f)(y)=y^3 - 3 y^2 +y\\\\(g \circ f)(-6)=(-6)^3-3\cdot(-6)^2+(-6)\\(g \circ f)(-6)=-216-108-6\\(g \circ f)(-6)=-330$

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In a sample of 138 tables, the average height was found to be 32.6in. with a variance of 2.8. Give a point estimate for the popu

vesna_86 [32]

Answer:

$\hat{\sigma}^2 = 2.8$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 138

Average = 32.6 inch

Population variance,

$\sigma^2 = 2.8$

We have to find a point estimate for the population variance of the height.

The point estimate for the population variance is the population variance itself.

$\hat{\sigma}^2 = \sigma^2 = 2.8$

Thus, the point estimate of population variance is the population variance that is 2.8.

5 0

3 years ago

HELP PLEASE AND THANK YOU 1JAAB

Dafna1 [17]

Answer:

$\bold{Q1}\ side\ BD\\\\\bold{Q2}\ \angle5\ \leftrightarrow\ \angle6\\\\\bold{Q3}\ \triangle TAP\\\\\bold{Q4}\ \triangle APT$

Step-by-step explanation:

For Q1 and Q2

$\text{If}\ AB\cong AC,\ BD\cong CD,\ RSTU\ \text{is a parallelogram (rectangle)},\ \text{then}\\\\\angle 1\ \leftrightarrow\ \angle2\\\angle3\ \leftrightarrow\ \angle4\\\angle C\leftrightarrow\ \angle B\\\angle 5\ \leftrightarrow\ \angle6\\\angle7\ \leftrightarrow\ \angle 8\\\angle R\ \leftrightarrow\ \angle T\\\angle S\ \leftrightarrow\ \angle U$

$\overline{AB}\ \leftrightarrow\ \overline{AC}\\\overline{BD}\ \leftrightarrow\ \overline{CD}\\\\\overline{RS}\ \leftrightarrow\ \overline{TU}\\\overline{ST}\ \leftrightarrow\ \overline{UR}$

For Q3 and Q4

$O\ \leftrightarrow\ T\\B\ \leftrightarrow\ A\\R\ \leftrightarrow\ P\\\\E\ \leftrightarrow\ X\\F\ \leftrightarrow\ W\\D\ \leftrightarrow\ T$

4 0

3 years ago

This isnt urgent but i need an answer, i will give the person who answers correctly brainliest, please try

SSSSS [86.1K]

Answer: 3, 5, 7

Step-by-step explanation:

There is a "trick" to determine divisibility by 3: if the sum of the digits is divisible by 3, the number is divisible by 3.

3 + 1 + 5 = 9 which is a multiple of 3, so 315 is divisible by 3.

It works for 9 also. since the sum of the digits is 9, 315 is divisible by 9.

Divisibility by 5: any number that has the units digit 5 or 0 is divisible by 5.

For 7, I just tried it 315÷7= 45

Only even numbers are divisible by 2.

If a 3-digit number is divisible by 11, the middle digit will be the sum of the first and last digits. (That is not the case for 315) But 385 is divisible by 11, also 495, 253, and many others you can try for fun.

8 0

3 years ago

Decimals from 7.0 to 8.4 with an interval of 0.2 between each pair of decimals

Vitek1552 [10]

Decimals from 7.0 to 8.4 with an interval of 0.2 between each pair of decimals

We start with 7.0 and keep adding 0.2 till we get 8.4

7.0 + 0.2 = 7.2

7.2 + 0.2 = 7.4

7.4 + 0.2 = 7.6

7.6 + 0.2 = 7.8

7.8 + 0.2 = 8.0

8.0 + 0.2 = 8.2

8.2 + 0.2 = 8.4

So, the decimals from 7.0 to 8.4 with an interval of 0.2 are

7.2, 7.4, 7.6, 7.8, 8.0, 8.2

3 0

3 years ago

Read 2 more answers

Multiply negative 1 over 2 multiplied by negative 1 over 2. Which of the following is correct?

krok68 [10]

Answer:

negative 1 over 4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers