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lianna [129]
3 years ago
10

Given that the f(y) = y - 1 and g(y) = y^3 - 2y - 1, find (gof) (y)I and hence, (gof) (-6).

Mathematics
1 answer:
nordsb [41]3 years ago
3 0

(g \circ f)(y)=(y-1)^3-2(y-1)-1\\(g \circ f)(y)=y^3 - 3 y^2 + 3 y - 1-2y+2-1\\(g \circ f)(y)=y^3 - 3 y^2 +y\\\\(g \circ f)(-6)=(-6)^3-3\cdot(-6)^2+(-6)\\(g \circ f)(-6)=-216-108-6\\(g \circ f)(-6)=-330

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Answer:

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The bottom triangle has dimensions of b=3, h=(√53)/4, so an area of ...

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<em>Additional comment</em>

Often we work with pyramids that are rotationally symmetrical about a vertical line through the peak. This one is not. The altitude of the bottom triangle in the net is less than the altitude of the other triangles. This short face of the pyramid will tend to be more vertical than the other two lateral faces.

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