Answer:
(a) Gg × Gg; (b) genotypic = 1:2:1, phenotypic = 3:1
Explanation:
a) A cross between two gray seeded plants produces progeny with gray and white seeds in 3:1 ratio (302:98=3:1). This means that the parent plants are heterozygous and each has at least one recessive allele. If the allele "G" is responsible for gray seed and the allele "g" imparts white color to the seeds, the genotype of the heterozygous parents would be "Gg".
b) A cross between two heterozygous gray seeded parents would produce progeny in following ratio:
Genotype ratio= 1 GG: 2 Gg: 1 gg
Phenotype ratio= 3 Gray: 1 white
Answer:
iAiA or iAi = Type A
Explanation:
Blood group in humans is controlled by a gene with multiple alleles. The alleles iA and iB are co-dominant over one another but dominant over allele i. In the blood type:
iAiA or iAi - type A
iBiB or iBi - type B
iAiB - type AB
ii - type O
According to this question, a man and a woman have a child together. The mother's blood type is type O (ii) and the child's blood type is type A (iAi). This means that the father's blood type must be a type A with genotype "iAiA or iAi".
I can't answer that perfectly, as there is a leap year every four years, but it should be 5,479 days. (365*15 + 4)
A= U, G= C, T= A You can reverse it as well to find the codons