2 years ago

How do you do number 16?

Mathematics

1 answer:

MA_775_DIABLO [31]2 years ago

7 0

The answer to this would be 1/5.
hope this helps

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Evalute p-4 for p=24

polet [3.4K]

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2 years ago

Read 2 more answers

Solve for 'p'

Darina [25.2K]

$\left(\dfrac{9a^{-4}}{25}\right)^p=\dfrac3{5a^2}$
$\left(\dfrac9{25a^4}\right)^p=\dfrac3{5a^2}$

One way to find $p$ is to notice that the part on the left hand side within the parentheses can be written as a square:

$\dfrac9{25a^4}=\dfrac{3^2}{5^2(a^2)^2}=\left(\dfrac3{5a^2}\right)^2$

So you could write

$\left(\left(\dfrac3{5a^2}\right)^2\right)^p=\left(\dfrac3{5a^2}\right)^{2p}=\dfrac3{5a^2}$

Since these two expressions are equal, and the bases are the same, you know the exponents must be equal, with the exponent on the right hand side being 1. So $2p=1$ , or $p=\dfrac12$ .

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3 years ago