Find the L.C.M and H.C.F of: a. 432 and 486
1 answer:
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Answer:
0.3898 = 38.98% probability that there will be 4 failures
Step-by-step explanation:
A sequence of Bernoulli trials forms the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Let the probability of success on a Bernoulli trial be 0.26.
This means that
a. In five Bernoulli trials, what is the probability that there will be 4 failures?
Five trials means that
4 failures, so 1 success, and we have to find P(X = 1).
0.3898 = 38.98% probability that there will be 4 failures
Answer:
A. number of decayed atoms = 73.197
Step-by-step explanation:
In order to find the answer we need to use the radioactive decay equation:
where:
N0=initial radioactive atoms
t=time
k=radioactive decay constant
In our case, when t=0 we have 1,000,000 atoms, so:
Now we need to find 'k'. Using the provied information that after 365 days we have 973,635 radioactive atoms, we have:
A. atoms decayed in a day:
Number of atoms decayed in a day = 1,000,000 - 999,926.803 = 73.197
B. Because 'k' represents the probability of decay, then the probability that on a given day 51 radioactive atoms decayed is k=0.0000732.