Answer:
Step-by-step explanation:
If you plot this point and the directrix on a coordinate plane, you can see that the directrix is 1/4 of a unit below the vertex. Since, by nature, a parabola opens in the direction opposite the directrix and "hugs" the focus, this is a positive x-squared parabola (meaning it opens upwards). The formula for this type of a parabola is, in vertex form,
![4p(y-k)=(x-h)^2](https://tex.z-dn.net/?f=4p%28y-k%29%3D%28x-h%29%5E2)
where p is distance (in units) between the vertex and the directrix and h and k are the coordinates of the vertex. For us, p = .25, h = 7, and k = -6. Filling in our formula:
![4(.25)(y+6)=(x-7)^2](https://tex.z-dn.net/?f=4%28.25%29%28y%2B6%29%3D%28x-7%29%5E2)
Simplify the left side to
which simplifies, in its entirety, to
![(x-7)^2-6=y](https://tex.z-dn.net/?f=%28x-7%29%5E2-6%3Dy)
Answer:
Correct answer: F. graph F or x ∈ |-5 ; 5| (including endpoints)
Step-by-step explanation:
Let us first define the absolute value:
| x | = 1. { x with condition x ≥ 0 }
or 2. { - x with condition x < 0 }
This is a linear inequality
1. x ≤ 5 ∧ x ≥ 0 ⇒ 0 ≤ x ≤ 5 or interval x ∈ |0 ; 5| (including endpoints)
2. - x ≤ 5 when we multiply both sides of the equation by -1 we get:
x ≥ -5 ∧ x < 0 ⇒ -5 ≤ x < 0 or interval x ∈ |-5 ; 0) (including -5)
The solution to this linear inequality is the union of these two intervals:
x ∈ |-5 ; 0) ∪ |0 ; 5| ⇒ x ∈ |-5 ; 5| (including endpoints)
x ∈ |-5 ; 5| (including endpoints)
God is with you!!!
Similarity implies correspondence. Angles are listed in the order in which they are congruent to one another. A is congruent to I, B is congruent to J, C is congruent to K, D is congruent to L.
Answer:
0.0066%
Step-by-step explanation: