You have two angles congruent, plus a side that's NOT between them.
I guess you'd call that situation " AAS " for "angle-angle-side".
That's what you have, and it's NOT enough to prove the triangles
congruent. There can be many many different pairs of triangles
that have AAS = AAS.
So there's no congruence postulate to cover this case, because they're
not necessarily.
Step-by-step explanation:
y+4z=0
4x+y-2z=2
-3x-3z=-9
<span>10 pounds of potatoes for $5.50
one pound = $5.50 / 10 = $0.55
answer
it cost 55 cents per pound</span>
Answer: False
Step-by-step explanation:
degrees of freedom=(r-1)(c-1)
I don't know if I'm exactly right
if not sorry
Answer: 3
Step-by-step explanation:
