Although a research question usually concerns the ____ the actual research participants are selected from the ___

A large field measures 70 feet by 525 feet. If you divide it up into equal square garden plots, what size would the largest poss

fenix001 [56]

9514 1404 393

Answer:

35 feet square

Step-by-step explanation:

The greatest common factor of 70 and 525 is 35. The largest square plot can be 35 feet on a side.

70 = 2·35

525 = 15·35

__

I like to find the GCD (greatest common divisor) using Euclid's algorithm. We find the remainder when dividing the larger by the smaller. When that remainder is not zero, we replace the larger number with the remainder, and repeat. When the remainder is zero, the divisor is the GCD.

525/70 = 7 r 35

70/35 = 2 r 0 . . . . . 35 is the GCD

7 0

3 years ago

Does the point (0,4) make either equations y=-2x and y=x+3 true? Explain.

Nikolay [14]

Answer:

Neither

Step-by-step explanation:

To verify, we substitute the values in the equations:

$y = -2x\\y = -2 \times 0\\y = 0$

however, the value should be 4. Hence this equation does not satisfy the co-ordinate.

$y = x+3\\y= 0+3\\y = 3$

however, the value should be 4. Hence this equation does not satisfy the co-ordinate.

5 0

3 years ago

5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim

Ne4ueva [31]

Answer:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

$S_p=2.940$

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

$df=60+72-2=130$

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

$n_1 =60$ represent the sample size for people who used a self service

$n_2 =72$ represent the sample size for people who used a cashier

$\bar X_1 =5.2$ represent the sample mean for people who used a self service

$\bar X_2 =6.1$ represent the sample mean people who used a cashier

$s_1=3.1$ represent the sample standard deviation for people who used a self service

$s_2=2.8$ represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

And t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

System of hypothesis

Null hypothesis: $\mu_1 \geq \mu_2$

Alternative hypothesis: $\mu_1 < \mu_2$

This system is equivalent to:

Null hypothesis: $\mu_1 - \mu_2 \geq 0$

Alternative hypothesis: $\mu_1 -\mu_2 < 0$

We can find the pooled variance:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

And the deviation would be just the square root of the variance:

$S_p=2.940$

The statistic is given by:

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

The degrees of freedom are given by:

$df=60+72-2=130$

And now we can calculate the p value with:

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0

3 years ago

What is the unit rate for 297 words in 5.5 minutes

Stolb23 [73]

297:5.5

divide 5.5 by both sides which

5.5 divided by 5.5 is 1 and 297 divided by 5.5 is 54

1:54

the unit rate:

54 minutes per word or 54/1

6 0

3 years ago

Read 2 more answers

9. Find the area of the figure to the right.<br> area<br> 14 in

zlopas [31]

Answer:

1. 200 in.^2

2.

Step-by-step explanation:

1. Area of a trapezium=1/2(a+b)height

a=14 in.

b=20 in.+6 in. = 26 in.

height= ?

height can be gotten by using

formula : Soh Cah Toa

Toa is tangent∆= opposite/ adjacent

∆ = 60°

opp=? adj=6 in.

Tan 60° =opp/6 in.

Tan 60° = 1.732

1.732= opp/ 6 in.

opp=1.732*6 in.

opp = 10.392 approximately= 10 in.

Area of trapezium= 1/2*(14+26)*10(in.^2)

Area of trapezium= 1/2*40*10

= 1/2*400

= 200 in.^2 .

2. Area of triangle= 1/2* base* height

for first triangle =

base=4m

height =15m

Area: 1/2*4*15 ,1/2*60= 30m^2

second triangle =

base:?

height: 15m

using Pythagorean theorem;

hyp^2 = opposite ^2 + adjacent ^2

17^2 = 15^2 + adj^2

289= 225 + adj^2

adj^2 = 289-225= 64

square root

adj = 8m

area of second triangle : 1/2*8*15

: 1/2*120 :60m^2

total area: 30 m^2 +60m^2

==90 m^2

8 0

3 years ago

Although a research question usually concerns the ____ the actual research participants are selected from the ____.

Although a research question usually concerns the the actual research participants are selected from the .