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igor_vitrenko [27]
3 years ago
8

You need to wrap a present that is in the shape of a rectangular prism the present has a length of 5 inches a width of 4.5 inche

s and a height and a height of 3.5 inches find the total surface area of the present
A. 111.5 in2

B. 55.75 in2

C. 95.75 in2

D. 135 in2
Mathematics
1 answer:
Vadim26 [7]3 years ago
5 0
The equation for surface area is 2(lw+lh+wh) or length times width plus length times height plus width times height times 2.

so in this problem legth=5 and width=4.5 so 5×4.5=22.5

length=5 height=3.5 so 5×3.5=17.5

width=4.5 height=3.5 so 4.5×3.5=15.75

add these together and you get 55.75.

now we multiply that by 2 so 55.75×2=111.5

so the surface area of the gift is (drumroll please) 111.5
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Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6.
Sophie [7]

Answer:

Step-by-step explanation:

Alright, lets get started.

using Sine Law,

\frac{sinA}{a}=\frac{sinB}{b}

\frac{sin30}{4}=\frac{sinB}{6}

sinB=0.75

angle B = 48.6

Another angle will be

angle B' = 180-48.6 = 131.4

considering angle B, angle C = 180 - (48.6+30)=101.4

considering angle B', angle C' = 180-(131.4+30)=18.6

\frac{sinA}{a}=\frac{sinC}{c}

\frac{sin30}{4}=\frac{sin101.4}{c}

c = 7.84

Similarly, finding c'

\frac{sinA}{a}=\frac{sinC'}{c'}

\frac{sin30}{4}=\frac{sin18.6}{c'}

c'=2.55

Hence two triangles are possible with below details:  :   Answer

A = 30, B = 48.6, C = 101.4, c = 7.84

A = 30, B' = 131.4, C' = 18.6, c' = 2.55

Hope it will help :)

5 0
3 years ago
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VladimirAG [237]

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8 0
3 years ago
i beg of yall a crown, 5 stars, a heart and a ty comment to answer my questions iv posted on my profile, ill be posting more too
Over [174]

Answer:

I would say the answer is $5.00/lb

Have a wonderful day!

6 0
2 years ago
Write 3x^2-18x-6 in vertex form
Vedmedyk [2.9K]
The standard form of a quadratic equation is \displaystyle{ y=ax^2+bx+c, while the vertex form is:

                      y=a(x-h)^2+k, where (h, k) is the vertex of the parabola.

What we want is to write \displaystyle{ y=3x^2-18x-6 as y=a(x-h)^2+k

First, we note that all the three terms have a factor of 3, so we factorize it and write:

\displaystyle{ y=3(x^2-6x-2).


Second, we notice that x^2-6x are the terms produced by (x-3)^2=x^2-6x+9, without the 9. So we can write:

x^2-6x=(x-3)^2-9, and substituting in \displaystyle{ y=3(x^2-6x-2) we have:

\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11].

Finally, distributing 3 over the two terms in the brackets we have:

y=3[x-3]^2-33.


Answer: y=3(x-3)^2-33
6 0
3 years ago
Match the terms to their correct definitions.
Andrews [41]

Answer:

i

Step-by-step explanation:

7 0
3 years ago
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