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3 years ago

15x = 5y - 5 y =3x + 1

Mathematics

1 answer:

sleet_krkn [62]3 years ago

7 0

Answer:

Point Form:

(x,1+3x)

Equation Form:

x=x,y=1+3x

Step-by-step explanation:

Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.

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Lady_Fox [76]

The 4th one is correct

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3 years ago

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25% of my number is 24 what number is sam thinking of

scoundrel [369]

Answer:

Step-by-step explanation:

25% is 1/4 of 100%

thus, if you multiply 24x4 you get 100%

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P=12 when q=8 and r=3

guapka [62]

<h3>we can make the below formulas with this information:</h3>

$1. \frac{p}{q} = r \\ 2.q \times r = p \\ 3. \frac{p}{r} = q \\ 4.\frac{q \times r}{p} = 1$

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3 years ago

6 is added a number x.then the result is multiplied by 9. the final answer is greater than 99

drek231 [11]

So this inequality is going to be written as 9(x + 6) > 99

Firstly, you want to foil 9(x + 6), which will look like this: 9x + 54 > 99

Next, subtract 54 on both sides of the equation: 9x > 45

Lastly, divide both sides by 9, and your answer will be x > 5

6 0

4 years ago

(1 point) Suppose we want a 95% confidence interval for the average amount spent on books by freshmen in their first year at col

Ne4ueva [31]

Answer:

a) $n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40$

So the answer for this case would be n=40 rounded up to the nearest integer

b) For this case if we see the formula for the margin of error

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean

$\sigma=16$ represent the population standard deviation

n represent the sample size

Solution to the problem

Part a

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40$

So the answer for this case would be n=40 rounded up to the nearest integer

Part b

For this case if we see the formula for the margin of error

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

5 0

3 years ago