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2 years ago

Can someone help me with this

Mathematics

1 answer:

Tems11 [23]2 years ago

4 0

Answer: 8.2

Step-by-step explanation:

As angles in a triangle add to 180 degrees,

$\angle A=180^{\circ}-121^{\circ}-31^{\circ}=28^{\circ}$

So, by the Law of Sines,

$\frac{a}{\sin A}=\frac{b}{\sin B}\\\\a=\frac{b \sin A}{\sin B}\\\\a=\frac{9 \sin 28^{\circ}}{\sin 31^{\circ}}\\\\a \approx \boxed{8.2}$

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Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

4 0

1 year ago

May anyone help please

lapo4ka [179]

Depending on how flexibly you interpret "about 20 times larger" to mean, the answers are B and D.

Check the ratios of the larger number to the smaller number:

A: (2.01 x 10^7)/(4.25 x 10^6) = 2.01/4.25 x 10^1 = 20.1/4.25 = 4.729

B: (8.21 x 10^-3)/(4.13 x 10^-4) = 8.21/4.13 x 10^1 = 82.1/4.13 = 19.879

C: (4.91 x 10^6)/(5.09 x 10^3) = 4.91/5.09 x 10^3 = 4910/5.09 = 964.637

D: (5.97 x 10^4)/(3.12 x 10^3) = 5.97/3.12 x 10^1 = 59.7/3.12 = 19.135

4 0

3 years ago

Solve for y.

Dmitry [639]

Answer:

y = 5

Step-by-step explanation:

if y = 5 then

(√10-1) -1 = 2

3 - 1 = 2

true

5 0

3 years ago

Read 2 more answers

Find the limit. use l'hospital's rule where appropriate. if there is a more elementary method, consider using it. lim x→0+ arcta

Thepotemich [5.8K]

The answer for your problem is shown on the picture.

8 0

3 years ago

The tens digit of a two-digit number is twice the units digit. If the digits are reversed, the new number is 36 less than the or

Ludmilka [50]

Try this solution:
let the unknown two-digits number be 'xy'.
Then it is possible to write any two-digit number as 10x+y, where x - the tens digit and y - the unit digit.
Using the rule described above the phrase 'the tens digit of a number is twice the units digit' may be written as x=2y.
Using the same rule the phrase 'if the digits are reversed, the new number is 36 is less than the original number' may be written as (10x+y)-(10y+x)=36.
These two equations may be resolved as system of two equations:
$\left \{ {{x=2y} \atop {10x+y-(10y+x)=36}} \right. \ =\ \textgreater \ \ \left \{ {{x=8} \atop {y=4}} \right.$
Check: the original number is 84, the new number is 48; difference is 84-48=36.

answer: 84

7 0

4 years ago