<span>3x^2y^2 − 2xy^2 − 8y^2 =
y^2 (3x^2 - 2x - 8) =
factoring with leading coefficient:
for ax2+bx+c find two numbers n,m, that m*n = a*c and m+n = b
</span><span><span>
3x^2 - 2x - 8
a=3, b=-2, c=-8
</span>a*c = 3*(-8) = -24
-24=(-6)*4 and -6+4=-2, so m=-6 and n=4
replace bx with mx + nx and factor by grouping
</span><span>
3x^2 - 2x - 8 = </span>3x^2 -6x + 4x -8 = 3x(x-2) + 4(x-2) = (3x+4)(x-2)
answer:
<span>3x^2y^2 − 2xy^2 − 8y^2 = y^2(3x+4)(x-2)</span>
Answer:
5.86
Step-by-step explanation:
the answer is X^3+6x<span>^2-7x+5
</span>
32 is ur answer
sorry if its wrong
Im bad at this
Answer:
Step-by-step explanation:
<u>Given function is:</u>
Put x = 4
So,
![f(4) = 4^4\\\\f(4) = 256\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=f%284%29%20%3D%204%5E4%5C%5C%5C%5Cf%284%29%20%3D%20256%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
