Answer:
h=0.89
Step-by-step explanation:
Given
Diameter=22m
so radius=11m
Volume=113m^3
Solution
1/3πr^2h=113
1/3×3.14×11×11h=113
h=113×3/3.14×11×11
h=0.89
So the value of h is 0.89
Answer:
4.91666666667
Step-by-step explanation:
1 1/3 + 1 5/6 + 1 3/4 = 4.91666666667
Something that a right triangle is characterised by is the fact that we may use Pythagoras' theorem to find the length of any one of its sides, given that we know the length of the other two sides. Here, we know the length of the hypotenuse and one other side, therefor we can easily use the theorem to solve for the remaining side.
Now, Pythagoras' Theorem is defined as follows:
c^2 = a^2 + b^2, where c is the length of the hypotenuse and a and b are the lengths of the other two sides.
Given that we know that c = 24 and a = 8, we can find b by substituting c and a into the formula we defined above:
c^2 = a^2 + b^2
24^2 = 8^2 + b^2 (Substitute c = 24 and a = 8)
b^2 = 24^2 - 8^2 (Subtract 8^2 from both sides)
b = √(24^2 - 8^2) (Take the square root of both sides)
b = √512 (Evaluate 24^2 - 8^2)
b = 16√2 (Simplify √512)
= 22.627 (to three decimal places)
I wasn't sure about whether by 'approximate length' you meant for the length to be rounded to a certain number of decimal places or whether you were meant to do more of an estimate based on your knowledge of surds and powers. If you need any more clarification however don't hesitate to comment below.
Answer:
N=-13
Step-by-step explanation:
Answer:
Converting the equation 
into completing the square method we get: 
Step-by-step explanation:
we are given quadratic equation:
And we need to convert it into completing the square method.
Completing the square method is of form: 
Looking at the given equation
We have a = x
then we have middle term 20x that can be written in form of 2ab So, we have a=x and b=? Multiplying 10 with 2 we get 20 so, we can say that b = 20
So, 20x in form of 2ab can be written as: 2(x)(10)
So, we need to add and subtract (10)^2 on both sides
So, converting the equation into completing the square method we get:
