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podryga [215]
3 years ago
8

is the relationship between the side length of a square and the area of the square an example of a function?

Mathematics
1 answer:
vekshin13 years ago
3 0
Yes. to find the area of a square when you know one side "s", you simply square that side since the area is equal to the base times the height, and the base and height will always be equal in a square since the sides are equal:

A = s^2 

Represented in a function form:

f(s) = s^2

This means whatever you plug in for s, you will square it to get the area.
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X + y = 4<br> y = -x + 4
rjkz [21]

Answer:

Infinite Solutions

Step-by-step explanation:

x + y = 4

y = -x + 4

x + y = 4

x - x + 4 = 4

0 = 0

5 0
2 years ago
Jodie measure a house and its pot and made a scale drawing. The scale of the drawing was 2 inches : 1 foot. If the actual length
Hoochie [10]

Answer:

Length of yard in the drawing is 148 inches

Step-by-step explanation:

The scale is 2in : 1ft

Hence x inches will be 74ft

X = (74×2)÷ 1 = 148 inches

5 0
3 years ago
Read 2 more answers
Use a graphing calculator to solve the equation -2sin(theta)= 1.2 in the interval from 0 to 2pi.
elena-s [515]

Answer:

\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64  

Step-by-step explanation:

As you can see from the graph I attached you, the possible solutions in the interval from 0 to 2π are approximately:

\theta=3.7\\\\and\\\\\theta=5.7

So, it's useful to solve the equation too, in order to verify the result:

-2sin(\theta)=1.2\\\\sin(\theta)=-\frac{3}{5}

Taking the inverse sine of both sides:

\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64

Using this result we can conclude the solutions in the interval from 0 to 2π are approximately:

\theta\approx 3.785\\\\\theta \approx 5.64

8 0
3 years ago
Find the range of (f+g)(x) when f(x) = (x+4)^2 and g(x) = 3
qwelly [4]

(f+g)(x)=f(x)+g(x)\\\\f(x)=(x+4)^2;\ g(x)=3\\\\(f+g)(x)=(x+4)^2+3=(x)^2+2(x)(4)+4^2+3\\\\=x^2+8x+16+3=x^2+8x+19\\\\Used:\\\\(a+b)^2=a^2+2ab+b^2

7 0
3 years ago
A pizza chain wants to send codes for $2 off a large pizza to the subscribers of its e-mail list. Each coupon code will have thr
kati45 [8]

Answer:

438,012 ways.

Step-by-step explanation:

We have been given that each coupon code will have three letters followed by two digits. The letters M, N, and O and the digits 1, 3, 5, and 7 will not be used. So, there are 23 letters and 6 digits that will be used.

Since the letters and digits can be repeated, so we will use fundamental principal of counting.

For first place, we can use 23 letters, for 2nd and 3rd place we can use 23 letters.

We can use 6 digits for 1st digit place and 6 digit for 2nd digit place as repetition is allowed.

So we can choose coupon code is following ways:

23\cdot 23\cdot 23\cdot 6\cdot 6=438012

Therefore, we can choose coupon codes in 438,012 ways.

3 0
3 years ago
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