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4 years ago

271+425 use rounding or compatible numbers to estimate the sum

Mathematics

1 answer:

Irina-Kira [14]4 years ago

6 0

271 rounded is 300, and 425 rounded is 400, so you could estimate the sum by adding 300 and 400, which equals 700.

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Solve 4^x+2=12 for x using the change of base formula logby=logy/logb

yulyashka [42]

Answer:

$x = \frac{1}{log(4)}$

Step-by-step explanation:

Here, the given expression is :

$4^x+2=12$

Now, simplifying the given expression ,we get:

$4^x+2=12 \implies 4^x=12 - 2 = 10\\\implies 4^x = 10$

Now, using the logarithmic property:

$log(b -y)=\frac{log (b)}{log(y)}$

$log(a^m) = m log(a)$

Now, in the expression $4^x = 10$ take log on the Both sides, we get:

$4^x = 10 \implies log( 4^x ) = log(10)\\\implies x log(4) = 1$

or, $x = \frac{1}{log(4)}$

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3 years ago

Tell whether the statement is true or false.

kherson [118]

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5 0

4 years ago

Read 2 more answers

Carol is single and has an adjusted gross income of $32,785. She claims one exemption of $8200. What is her tax due?

LenKa [72]

Answer

A = 3321

Step-by-step explanation:

The reason for this answer is to get the Taxable income, you go by this equation AGI - (Exemptions + Deductions) since there is no deductions here we leave that part out. Subtract the AGI (32785) - 8200 the Exemption and you get 24585 then if we look on the chart, she is single and she falls under the answer of 3321!

Hope this helps, sorry I am a little late. I just got this answer too. :)

8 0

4 years ago

Four pounds of apples cost 3.88. what is the price per pound

Novay_Z [31]

Answer:

0.97 cents

Step-by-step explanation:

4/3.88=0.97

price per pound=0.97 cents

BRAINLIEST APPRECIATED!

HOPE YOU ARE HAVING A GOOD DAY!

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4 years ago

Your engineering firm is asked to specify the maximum load for the elevators in a new building: Each elevator has mass 490 kg wh

steposvetlana [31]

Answer:

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Step-by-step explanation:

The first step is to calculate the maximum load after safety considerations ( $T_{max}$

Since we know that the maximum tension the cables can withstand is 19500N (or 19.5kN). To calculate ( $T_{max}$ we multiply this value by $\frac{2}{3}$ (as per the given safety consideration.