Answer:
the second one and third one
Step-by-step explanation:
54 I'm pretty sure, sorry if I'm wrong
Answer:
0.4
Step-by-step explanation:
Given that:
P(debt) = P(D) = Probability of being in debt = 0.7
P(debt n Midwest) = P(Dn M) = probability of being in debt and lives in Midwest = 0.280
The probability that a randomly selected farmer lives in the Midwest given that he is in debt is?
P(M | D) = p(D n M) / p(D)
P(M | D) = 0.280 / 0.7
P(M | D) = 0.4
Answer:
The sample space for selecting the group to test contains <u>2,300</u> elementary events.
Step-by-step explanation:
There are a total of <em>N</em> = 25 aluminum castings.
Of these 25 aluminum castings, <em>n</em>₁ = 4 castings are defective (D) and <em>n</em>₂ = 21 are good (G).
It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.
In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.
The formula to compute the combinations of k items from n is given by the formula:

Compute the number of samples that are possible as follows:


The sample space for selecting the group to test contains <u>2,300</u> elementary events.