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Masteriza [31]
3 years ago
8

Does anyone knows how to solve this question??

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
8 0

Answer:

24

Step-by-step explanation:

cos(x) is just a trigonometric function. To find it on a right triangle, you take the "adjacent" side, which should be the side next to the angle x, and divide it by the hypotenuse.

In this case, the adjacent side is 12. We don't know the hypotenuse, but we can figure it out using the Pythagorean Theorem: \sqrt{9^{2}+12^{2}} = \sqrt{225} = 15. So, the hypotenuse is 15.

Thus, cos(x) = 12/15 = 4/5. We want 30 * cos(x), so we get: 30 * (4/5) = 24, and that is our answer.

Ilya [14]3 years ago
7 0

Answer:

24

Step-by-step explanation:

From the mnemonic SOHCAHTOA you would know that cos x = adjacent/hypotenuse.

Adjacent side is given as 12, but we must calculate the hypotenuse.

For that we use Pythagoras.

hypotenuse = √(9²+12²) = 15

Now you can calculate

30×cos(x) = 30×12/15 = 24

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3 years ago
Find the value of 4^2 + 6 ÷ 2
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Answer:

19

Step-by-step explanation:

Follow PEMDAS

4^2 + 6 ÷ 2

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3 years ago
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Using x and y as the numbers

x+y=25 -------#1
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x+y+x-y= 25+9
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2x=34
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Using the value of x and plugging said value into #1 or #2, we can find y
x=17

x+y=25
17+y=25
y=8

OR

x-y=9
17-y=9
-y=-8
y=8

The numbers are 8 and 17
5 0
3 years ago
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2sin^2 2x=2<br><br> In the domain [0,2pi)<br><br> What can x equal ( in radians).
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Bear in mind that, when it comes to trigonometric functions, the location of the exponent can be a bit misleading, however recall that sin²(θ) is really [ sin( θ )]²,


\bf 2sin^2(2x)=2\implies sin^2(2x)=\cfrac{2}{2}&#10;\\\\\\&#10;sin^2(2x)=1\implies [sin(2x)]^2=1\implies sin(2x)=\pm\sqrt{1}&#10;\\\\\\&#10;sin(2x)=\pm 1\implies sin^{-1}[sin(2x)]=sin^{-1}(\pm 1)

\bf \measuredangle 2x=sin^{-1}(\pm 1)\implies \measuredangle 2x=&#10;\begin{cases}&#10;\frac{\pi }{2}\\\\&#10;\frac{3\pi }{2}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\measuredangle 2x=\cfrac{\pi }{2}\implies \measuredangle x=\cfrac{\pi }{4}\qquad \qquad \qquad \qquad \measuredangle 2x=\cfrac{3\pi }{2}\implies \measuredangle x=\cfrac{3\pi }{4}
3 0
3 years ago
14, 15 and 16 please
WARRIOR [948]
14). (Take π value as 22/7)
circumference = 66in
2πr = 66in
2×22/7×r = 66
r = 66×7/2×22
r = 21/2in
d = 2r => d = 2×21/2
therefore diameter of the circle = 21in

15). (Take π value as 3.14)
Circumference = 3.14m
2πr = 3.14m
2×3.14×r = 3.14
r = 3.14/3.14×2
r = 1/2m
Therefore the radius of the circle = 0.5m

16). (Take π value as 22/7)
Circumference = 33km
2πr = 33km
2×22/7×r = 33
r = 33×7/2×22
r = 21/4
d = 2r
d = 2×21/4
d = 21/2km
Therefore the diameter of the circle = 10.5km
4 0
3 years ago
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