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Evgesh-ka [11]
2 years ago
13

Select all the correct answers.

Mathematics
2 answers:
Pavlova-9 [17]2 years ago
7 0
D.) A reflection of the shape across the y-axis and an 180 degree rotation around the orgin
kodGreya [7K]2 years ago
3 0

We will start answering this question by considering at the options.

1. When we reflect the shape I along X axis it will take the shape I in first quadrant, and then if we rotate the shape I by 90° clockwise, it will take the shape again in second quadrant . So we are not getting shape II. This Option is Incorrect.

2. Second Option is correct , because by reflecting the shape I across  X axis and then by 90° counterclockwise rotation will take the Shape I in second quadrant ,where we are getting shape II.

3. a reflection of shape I across the y-axis followed by a 90° counterclockwise rotation about the origin takes the shape I in fourth Quadrant. →→ Incorrect option.

4. This option is correct, because after reflecting the shape through Y axis ,and then rotating the shape through an angle of 90° in clockwise direction takes it in second quadrant.

5. A reflection of shape I across the x-axis followed by a 180° rotation about the origin takes the shape I in third quadrant.→→Incorrect option

→→Out of Five option given , Option (2) and Option (4) are true options.

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Rama09 [41]
X^2 + 12x + n
x^2 + 12x + (12/2)^2
x^2 + 12x + 6^2
n = 36
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6 0
3 years ago
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choli [55]

Answer: 12

Step-by-step explanation:

\frac{6}{18}=\frac{4}{c}

Solve for c

c=\frac{4*18}{6}\\ c=\frac{72}{6} \\c=12

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What is the equation for nine more than half of a number is 21
timurjin [86]

Answer: ×/2 + 9 =

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Answer:idk the answer just doing this for the B

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8 0
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Read 2 more answers
If you need $8000 to travel to Europe after you graduate in 4 year. How much would your monthly deposits need to be if your acco
lina2011 [118]
\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}\to &
\begin{array}{llll}
8000
\end{array}\\
pymnt=\textit{periodic payments}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12\\
t=years\to &4
\end{cases}

\bf 8000=pymnt\left[ \cfrac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]
\\\\\\
\cfrac{8000}{\left[ \frac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]}=pymnt\implies \cfrac{8000}{\frac{\left( \frac{241}{240} \right)^{48}-1}{\frac{1}{240}}}=pymnt
\\\\\\
\cfrac{8000}{53.0148852}\approx pymnt\implies 150.9010152318\approx pymnt
6 0
3 years ago
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