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3 years ago

12

Solve the equation cos(x + 60) =2sinx

1 answer:

iren [92.7K]3 years ago

5 0

Answer:

x ≈ 2.62971017 + π n

Step-by-step explanation:

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If <br> A = 6<br> B = 9<br> C = 15<br><br> Then what is D equal to?

Semmy [17]

A = 6
B = 9
C = 15
D = ?

From A to B, 6 + 3 = 9
From B to C, 9 + 6 = 15
From C to D, 9 + x = ?

The first time, you added 3, for the second time, you added three to the three you are adding, making it 6. So for x, x = 6 + 3, which = 9

9 + 9 = 18

D = 18 should be your answer

hope this helps

6 0

3 years ago

Solve for x.<br><br> 16 = -2x - 1<br><br> Solve for x.<br><br> 16 = -2x - 1<br><br> pls

kupik [55]

Answer:

1. 7

Step-by-step explanation:

4 0

3 years ago

Find the taylor polynomial t3(x) for the function f centered at the number

inysia [295]

Answer:

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3$

Step-by-step explanation:

We are given that

$f(x)=7tan^{-1}(x)$

a=1

$T_n(x)=\sum_{r=0}^{n}\frac{f^r(a)(x-a)^r}{r!}$

Substitute n=3 and a=1

$t_3(x)=f(1)+f'(1)(x-1)+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}$

$f(x)=7tan^{-1}(x)$

$f(1)=7tan^{-1}(1)=7\times \frac{\pi}{4}=\frac{7\pi}{4}$

Where $tan^{-1}(1)=\frac{\pi}{4}$

$f'(x)=\frac{7}{1+x^2}$

Using the formula

$\frac{d(tan^{-1}(x))}{dx}=\frac{1}{1+x^2}$

$f'(1)=\frac{7}{2}$

$f''(x)=\frac{-14x}{(1+x^2)^2}$

$f''(1)=-\frac{7}{2}$

$f''(x)=-14x(x^2+1)^{-2}$

$f'''(x)=-14((x^2+1)^{-2}-4x^2(x^2+1)^{-3}})$

By using the formula

$(uv)'=u'v+v'u$

$f'''(x)=-14(\frac{x^2+1-4x^2}{(1+x^2)^3}$

$f'''(x)=(-14)\frac{-3x^2+1}{(1+x^2)^3}$

$f'''(1)=-14(\frac{-3(1)+1}{2^3})=\frac{7}{2}$

Substitute the values

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{2\times 3\times 2\times 1}(x-1)^3$

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3$

7 0

3 years ago

If someone picks you as the brainiest or wutever, wut does that do?

olasank [31]

I think it just gives the other person 3 points but idk

6 0

3 years ago

Six out 8 teachers prefer expo markers to non bran markers. What is the ratio of teachers who do not prefer expo markers to thos

Sauron [17]

Answer:

2 to 6

Step-by-step explanation:

If 6 teachers prefer expo markers then 6-8=2 then there are two teachers that don't prefer markers and 6 that do so the equals 2:6

6 0

3 years ago

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