<span> Given polynomial x^2+8x-48 = 0</span>
<span>x^2+12x-4x-48 = 0</span>
<span>x(x+12)-4(x+12) = 0</span>
<span>(x+12)(x-4) = 0</span>
<span>x+12 = 0</span>
Subtract 12 from each side.
<span>x+12-12 = 0-12</span>
<span>x = -12</span>
<span>and x-4 = 0</span>
Add 4 to each side.
<span>x-4+4 = 0+4</span>
<span>x = 4</span>
<span>Roots are -12,4.</span>
Separate them first.
7+8=15
5/6+2/6=7/6
There can't be 7/6, so it becomes 1 and 1/6,
15+1+1/6=16 1/6
The answer is 16 1/6.
Answer:
5
Step-by-step explanation:
To solve a problem with negatives, we use the following rule.
If it is like
x+(-y), it is equivalent to x-y
If the equation is like
(-x)-(-y), it is equivalent to (-x)+y
So,
5+(-11)=5-11=-6
(-6)-(-11)=(-6)+11=5
Your answer is 5.
Step-by-step explanation:
a < (a + b)/2 < b
Solve the first inequality.
a < (a + b)/2
2a < a + b
a < b
Solve the second inequality.
(a + b)/2 < b
a + b < 2b
a < b
Both inequalities are true. Therefore, a < (a + b)/2 < b.
You’re answer could be either the first or last one