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kap26 [50]
3 years ago
9

Use the discriminant to describe the roots of each equation. Then select the best description.

Mathematics
1 answer:
Marrrta [24]3 years ago
4 0
Let's find the discriminant of <span>x^2+9x+14=0.  Here, a=1, b=9 and c=14.

The discriminant is b^2-4ac.  Substituting the above numeric values,
                                9^2-4(1)(14) = 81-56 = 25

The sqrt of 25 is 5.  Thus, your polynomial has two unequal, real roots.

Off the point example:  If the discriminant were zero, your poly would have two real, equal roots.</span>
You might be interested in
Convert 11.42424242 … to a rational expression in the form of , where b ≠ 0.
statuscvo [17]

I think it is the second one but im not for sure 

I hope that helped you

4 0
3 years ago
The equation of a circle whose center is (3,-2) and r =29
Degger [83]

Answer:

equation on circle: (x-h)^2 + (y-k)^2 =r^2

(x-3)^2 + (y+2)^2 = 841

7 0
2 years ago
Read 2 more answers
Find the height of the triangle by applying formulas for the area of a triangle and
lina2011 [118]

Answer:

Step-by-step explanation:

a= 12 mm ; b = 16 mm  ; c = 18 mm

s = (a + b+c)/2

=\dfrac{12 + 16 + 8}{2}\\\\= \dfrac{36}{2}\\\\= 18\\\\

s -a =  18 -  12 = 6 mm

s  -b = 18 - 16 = 2 mm

s  -c = 18 - 8 = 10 mm

area = \sqrt{s(s -a)(s-b)(s-c)}

       = \sqrt{18*6*2*10}\\\\= \sqrt{2160 }\\\\=46.47\\\\=46 \ mm^{2}\\

\dfrac{1}{2}* \ base * \ height = 46\\\\\dfrac{1}{2}*16* \ height = 46\\\\height = \dfrac{46*2}{16}\\\\

  = 5.75

Height = 5.8 mm

8 0
2 years ago
Read 2 more answers
If a triangle is a right triangle then the other two angles must be acute true or false ?
kolezko [41]

Answer:

The sum of the angles in any triangle is 180 degrees. If one of the three angles is 90 degrees (a right angle) the the sum of the other two angles is 90 degrees. Therefore each of the other two angles must be acute.

The statement is TRUE.

Step-by-step explanation:


8 0
3 years ago
Combine like terms: 3p2q2-3p2q3+4p2q3-3p2q2+pq PLEASE HELP!!! ASAP!!!
ch4aika [34]

Answer:

p²q³ + pq and pq(pq² + 1)

Step-by-step explanation:

Given

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Required

Collect like terms

We start by rewriting the expression

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Collect like terms

3p²q² -3p²q² - 3p²q³ +4p²q³ + pq

Group like terms

(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq

Perform arithmetic operations on like terms

(0) - (-p²q³) + pq

- (-p²q³) + pq

Open bracket

p²q³ + pq

The answer can be further simplified

Factorize p²q³ + pq

pq(pq² + 1)

Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)

7 0
3 years ago
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