1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nataliya [291]
4 years ago
13

And really likes cake. She desires that serving should be 3/5 of a cake. She has 4 cakes. How many servings does she have?

Mathematics
1 answer:
DENIUS [597]4 years ago
6 0
2 2/5 servings of cake
www.mathpapa.com algebra calculator, it is good

You might be interested in
What is the median of these numbers :<br> 6,7,7,8,8,4,7,6,4,6,8,7
jenyasd209 [6]

Answer:

7

Step-by-step explanation:

4,4,6,6,6,7,7,7,7,8,8

4,6,6,6,7,7,7,7,8

6,6,6,7,7,7,7

6,6,7,7,7

6,7,7

7

4 0
3 years ago
Read 2 more answers
HELP MEEEEE<br><br> Write 77% as a decimal.
kicyunya [14]

Answer:0.77

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!​
Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

\frac{3}{x + 4}  - \frac{1}{x + 3}  = \frac{x + 9}{(x^2 + 7x + 12)}

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

\frac{3*(x + 4)}{x + 4}  - \frac{(x + 4)}{x + 3}  = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}

3  - \frac{(x + 4)}{x + 3}  = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}

Now we can multiply both sides by (x + 3)

3*(x + 3)  - \frac{(x + 4)*(x+3)}{x + 3}  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

3*(x + 3)  - (x + 4)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

(2*x + 5)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

Now we can multiply both sides by (x^2 + 7*x + 12)

(2*x + 5)*(x^2 + 7x + 12)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)

(2*x + 5)*(x^2 + 7x + 12)  = (x + 9)*(x + 4)*(x+3)

Now we need to solve this:

we will get

2*x^3 + 19*x^2 + 59*x + 60 =  (x^2 + 13*x + 3)*(x + 3)

2*x^3 + 19*x^2 + 59*x + 60 =  x^3 + 16*x^2 + 42*x + 9

Then we get:

2*x^3 + 19*x^2 + 59*x + 60 - (  x^3 + 16*x^2 + 42*x + 9) = 0

x^3 + 3x^2 + 17*x + 51 = 0

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0
3 years ago
PLSSS HELP IF YOU TURLY KNOW THISS
Novay_Z [31]

Answer:

18225

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the range for a x intercept of (5,0) and a y intercept of (0,3)
Nastasia [14]

Answer:

(5,0)=x1,y1

(0,3)=x2,y2

so the range will be x1-x2/

3 0
3 years ago
Other questions:
  • Hey can you guys help me please help
    15·1 answer
  • What is the thousands place of 920
    6·1 answer
  • Point C is located at (2,8). If it is reflected across the x axis, where will C be located?
    9·2 answers
  • If you had 5,3 and moved left 2 units and 1 unit down
    13·1 answer
  • Ten less than 5 times the value of a number is equal to 10 times the quantity of
    13·1 answer
  • I need the answer can someone please help me!!
    12·1 answer
  • Help me! thank you so much
    7·1 answer
  • Predict the missing component of each reaction.
    8·2 answers
  • A rectangular prism has a volume of 2,340 cubic
    12·1 answer
  • What is the area of the figure?​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!