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maw [93]
3 years ago
10

The equation of motion for a weight suspended from a particular spring is given by p(t)=2sint3+5cost3p(t)=2sin⁡t3+5cos⁡t3, where

p(t)p(t) is the displacement from the equilibrium position in centimeters, and tt is the time elapsed in seconds. at what time does the weight first reach the equilibrium position?

Mathematics
1 answer:
daser333 [38]3 years ago
4 0
The given displacement at time, t, is
p(t) = 2 sin(t³) + 5 cos(t³)

The initial equilibrium position is
p(0) = 5

To determine future equilibrium postions, define
f(t) = p(t) - 5 = 2 sin(t³) + 5 cos(t³ - 5
The derivative of f(t) is
f'(t) = (3t²)[2 cos(t³) - 5sin(t³)]

Equilibrium is established when f(t) = 0.
To solve this equation numerically, we shall use the Newton-Raphson method, given by.
t(n+1) = t(n) - f[t(n)]/f'[(t(n)], n=0,1,2, ...,

As a guess, let (0) = 1.
The iterative solution for t is shown below.

  n         t(n)
 ---   -----------
   0   1.0000
   1    0.9344
   2   0.9147
   3   0.9130
   4   0.9130

The solution converges rapidly to t = 0.913 s.
The graphical solution (shown below) confirms the numerical solution.

Answer:
The weight first reaches the equilibrium position in 0.913 sec.

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A geometric sequence is a sequence of numbers where the next term equals to
exis [7]

Answer:

C

Step-by-step explanation:

Let the first term be a and the common ratio be r.

ATQ, ar^4=24 and ar^6=144, r=sqrt(6) and a=24/(sqrt(6))^2=24/36=2/3

4 0
3 years ago
A school debate team has four girls and six boys. A total of four of the team members will be chosen to participate in the distr
alex41 [277]
Procedure:

1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)

Solution

1) the number of teams of four members that can be formed are:

10*9*8*7 / (4*3*2*1) = 210

2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls

Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6

Number of different teams with 2 boys and 2 girls = 15 * 6 = 90

3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:

90/210 = 3/7
 
7 0
3 years ago
Given a function described as equation y=3x+4, what is y when x is 1,2 and 3?
koban [17]

Answer:

x=1 y= 7

x=2 y= 10

x=3 y= 13

Step-by-step explanation:

y=3x+4

y=3(1)+4

=7

y=3(2)+4

=-10

y=3(3)+4

=13

4 0
3 years ago
Read 2 more answers
when full the gas tank of a car holds 15 gallons. it now contains 12 gallons. what percent represents how full the tank is?
Masteriza [31]

Hello!

to find the percent of a whole, use this equation here:

(remaining) / (total) = X

X * 100 = %

in this case:

12 / 15 = 0.8

0.8 * 100 = 80

your answer is 80%

I hope this helps, and have a nice day!

5 0
2 years ago
Now I need help pplz
loris [4]
25 hope it helps (;......

3 0
3 years ago
Read 2 more answers
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