Answer:
x=
7/3
x=-4
Step-by-step explanation:
Use the quadratic formula
a= 3, b=5, c=-28
-5± 
x= _________________
2.3
Simplfy
X=- 4/5
X=-0.8
That’s the answer to your problem to your question
Answer:
See proof below
Step-by-step explanation:
show that
sinx/1+cosx=tanx/2
From LHS
sinx/1+cosx
According to half angle
sinx = 2sinx/2 cosx/2
cosx = cos²x/2 - sin²x/2
cosx = cos²x/2 - (1- cos²x/2)
cosx = 2cos²x/2 - 1
cos x + 1 = 2cos²x/2
Substitute into the expression;
sinx/1+cosx
= (2sinx/2 cosx/2)/2cos²x/2
= sinx.2/cos x/2
Since tan x = sinx/cosx
Hence sinx/2/cos x/2 = tan x/2 (RHS)
This shows that sinx/1+cosx=tanx/2
If you are asking if your work is good,thn yes,you are right
The first set:
3x + 2y = 2 ---1)
5x + 4y = 6 ---2)
From 1), multiply all by 2, 6x + 4y = 4 ---3)
3) - 2),
6x + 4y - (5x + 4y) = 6 - 4
6x + 4y - 5x - 4y = 2
x = 2
Sub in x = 2 into 1),
3(2) + 2y = 2
2y = -4
y = -2
(2 , -2)
The second set:
3x + 2y = 2 ---1)
11x + 8y = 10 ---2)
From 1), multiply all by 4, 12x + 8y = 8 ---3)
3) - 2),
12x + 8y - (11x + 8y) = 8 - 10
12x + 8y - 11x - 8y = -2
x = -2
From this x value alone, we can tell that these two linear systems do NOT have the same solution as they meet at different coordinates.
Hope this helped! Ask me if there's any working from here that you don't understand! :)
