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damaskus [11]
1 year ago
10

Helpp me pls I'm struggling

Mathematics
2 answers:
icang [17]1 year ago
4 0
B. 2nd play the first play list them yard because it’s a negative
Ierofanga [76]1 year ago
3 0

Answer:

B. 2nd Play and B. 2nd Play

Step-by-step explanation:

#1) Going negative means going backwards.

-8<10.5

#2) Absolute value means making all numbers INSIDE the two lines positive.

I-8I = 8

I10.5I = 10.5

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Consider the following events for a driver selected at random from a general population.
adoni [48]

Answer:

a. P(AnB)

b. P(B|A)

c. P(A^I|B)

d. P(A or B)

e. P(B^I or A)

Step-by-step explanation:

Since  A= driver is under 25 years old (1)

B = driver has received a speeding ticket (2)

a.The probability the driver is under 25 years old and has recieved a speeding ticket.

this simple means the intersection of both set, which can be written as

P(AnB)

b. The probability a driver who is under 25 years old has received a speeding ticket.

This is a conditional probability, probability that B will occur given that A as occur.

P(B|A)

c. the probability a driver who has received a speeding ticket is 25 years or older.

P(A^I|B)

d. The probability the driver is under 25 years old or has received a speeding ticket.

P(A or B)

e. The probability the driver is under 25 years old or has not received a speeding ticket.

P(B^I or A)

4 0
3 years ago
Find the degree.<br> 18x^4 y2 + 2x^5
lilavasa [31]

Answer:

answer is 5

Step-by-step explanation:

I used a calculator

8 0
3 years ago
Read 2 more answers
PLEASE PLEASE PLEASE HELP! Please explain step by step!! Please please I'll give enough points!
ArbitrLikvidat [17]
1)
The distance between points A and B is;
d= \sqrt{(x2-x1)^{2} + (y2-y1)^{2} } \\&#10;d= \sqrt{(1-5)^{2} +(12+8)^{2}}\\ &#10;d= \sqrt{(-4)^{2} + (20)^{2}}\\&#10;d=\sqrt{16+400}\\&#10;d=\sqrt{416}\\&#10;d=4\sqrt{26}, 
and if you wanted to you could measure out the legs of that hypotenuse using the slope between A and B, but I'm going to show you the easier way;
Δx = 4
Δy = -20
So from the midpoint, add 4 to the x-value and subract 20 from the y-value.
{(5+4),(-8-20)}
(9,-28) is the endpoint.

2)
Do the same thing as I did above;
d= \sqrt{(x2-x1)^{2} + (y2-y1)^{2} } \\ &#10;d= \sqrt{(5-(-3))^{2} +(5-(-4))^{2}}\\&#10;d=\sqrt{(5+8)^{2}+(5+4)^{2}}\\&#10;d=\sqrt{(13)^{2}+(9)^{2}}\\&#10;d=\sqrt{169+81}\\&#10;d=\sqrt{250}\\&#10;d=5\sqrt{10}
So 5\sqrt{10} is the distance.

Sorry for the delay, life delayed me a ton ,:D
4 0
3 years ago
What does the fundamental theorem of algebra state about the equation 2x^2−6x+10=0 ?
Temka [501]

Answer:

B. The fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. The roots are ​ x=3±i√11/2 .  

Step-by-step explanation:

We know that,

Fundamental theorem of algebra states that ' a polynomial of degree n will have n number of roots'.

Since, the polynomial y=2x^{2}-6x+10 has degree 2, so it will have 2 roots.

We know that the polynomial ax^{2}+bx+c=0 has roots given by x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}.

So, the roots of polynomial 2x^{2}-6x+10=0 will be,

x=\frac{6 \pm \sqrt{(-6)^{2}-4 \times 2 \times 10}}{2 \times 2}

i.e. x=\frac{6 \pm \sqrt{36-80}}{4}

i.e. x=\frac{6 \pm \sqrt{-44}}{4}

i.e. x=\frac{6 \pm 2i \sqrt{11}}{4}

i.e. x=3 \pm \frac{\sqrt{11}i}{2}

Hence, the roots are given by 3 \pm \frac{\sqrt{11}i}{2}

So, option B is correct.

5 0
3 years ago
Consider the following scenario. Bob is playing a board game where he blindly picks a tile from a container and moves some space
postnew [5]
The game is fair. 

Pls. see my attachment. 

Download pdf
7 0
3 years ago
Read 2 more answers
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