Easy peasy
the average rate of change in section A is the slope from (1,g(1)) to (2,g(2))
the average rate of chagne in section B is the slope from (3,g(3)) to (4,g(4))
A.
section A
g(1)=4(3)^1=12
g(2)=4(3)^2=4(9)=36
slope=(36-12)/(2-1)=24/1=24
section B
g(3)=4(3)^3=4(27)=108
g(4)=4(3)^4=4(81)=324
slope=(324-108)/(4-3)=216/1=216
section A has an average rate of change of 24
section B has an average rate of change of 216
Answer:
1) y=8/3=2 2/3 2) x=4 3) x+10
Step-by-step explanation:
1) 10+5-7=3y
Calculate the sum or difference.
8=3y
Swap the sides of the equation.
3y=8
Divide both sides by 3.
y=8/3=2 2/3
2) -10x+5x+5=-15
Collect like terms.
-5x+5=-15
Move the constant to the right-hand side and change the sign.
-5x=-15-5
Calculate the difference.
-5x=-20
Divide both sides by -5.
x=4
3) 3x+2x-4x+10
Collect like terms.
(3+2-4)x+10
Calculate the sum or difference.
1x+10
When the term has a coefficient of 1, it doesn't have to be written.
x+10
Hope this helps :)
Answer:
<h3>-cos10°</h3>
Step-by-step explanation:
cos is positive at first and fourth quadrant
so, cos (-x) = cos (x)
also, cos(180-x) = -cos x
cos (180+x) = -cos x
cos (-170°) = cos (170°)
cos(170°) = cos (180° - 10°)
= - cos 10°
