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vladimir2022 [97]
3 years ago
11

Shazia sells 25x^2+5x+5 flowers in one day. If she sells the same number of flowers each day for rs 5x each , how much money wil

l she have at the end of five days
Mathematics
1 answer:
kotykmax [81]3 years ago
3 0

Answer:

<h2>350<em><u> </u></em><em><u>THATS</u></em><em><u> </u></em><em><u>THE</u></em><em><u> </u></em><em><u>ANSWER</u></em><em><u> </u></em><em><u>IF</u></em><em><u> </u></em><em><u>IM</u></em><em><u> </u></em><em><u>WRONG</u></em><em><u> </u></em><em><u>CORRECT</u></em><em><u> </u></em><em><u>ME</u></em></h2>
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tom opens a bank account and makes an initial investment of $500 the banker tells tom that he is going to recive and annula rate
aliya0001 [1]

Answer:

$950

Step-by-step explanation:

(500*6*15)/100 = 450 (applying the formula of simple interest)

450 + 500 ( adding the interest to the initial investment or princlple)

= 950 (bank balance after 15 years)

Hope this helps! :)

7 0
3 years ago
A line has a slope of-5/3 and y intercept of 6 which of the following is an equation of the line
noname [10]

Answer:

y=-5/3+6

Step-by-step explanation:

y=mx+b

m is the slope

b is the y-intercept

y=-5/3+6

3 0
3 years ago
Read 2 more answers
Write each fraction or mixed number as the sum of fractions in two different ways 1 1/4 and 1 3/5
DENIUS [597]
1 1/4 = 5/4 

1 3/5=  8/5
8 0
3 years ago
The inequality 10.45b + 56.50 &lt; 292.67 is used to find the number of boxes (b) that can be loaded on a truck without exceedin
nordsb [41]

Question :

The inequality 10.45b + 56.50 < 292.67 is used to find the number of boxes (b) that can be loaded on a truck without exceeding the weight limit of the truck. The solution is written as {b | b < 22.6}. Which statement best describes the meaning of the solution?

The truck can hold more than 22 boxes.

The truck can hold more than 23 boxes.

The truck can hold up to 22 boxes.

The truck can hold up to 23 boxes.

Answer:

Option C: The truck can hold up to 22 boxes.

Explanation:

Given that the inequality is 10.45b + 56.50 < 292.67 is used to find the number of boxes can be loaded on a truck without exceeding the weight limit of the truck.

To determine the number of boxes, let us solve the inequality.

Thus, we have,

10.45b + 56.50 < 292.67

Subtracting both sides by 56.50, we get,

10.45b  < 236.17

Dividing both sides by 10.45, we have,

b

This means that the number of boxes that can be loaded on a truck without exceeding the weight limit of the truck should be lesser than 22.6

Therefore, the truck can hold up to 22 boxes.

Hence, Option C is the correct answer.

4 0
3 years ago
Read 2 more answers
How to do linear equations 27, 28,28,30
Mekhanik [1.2K]
#27.  
First cross multiply
2 (2a-3) = 3 (a-1)
next use the distribute property on both sides
4a - 6 = 3a - 3
combine like terms, subtract 3a from both sides and add 6 to both sides
a = 3

#28
cross multiply
3x = 4, then divide both sides by 3
x = 4/3

#30
add 1/4 to both sides
3/x = 1/2 + 1/4, find a common denominator for the right side fractions
3/x = 2/4 + 1/4 = 3/4
therefore, x = 4
6 0
3 years ago
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