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yanalaym [24]
3 years ago
11

Explain why the numerical expression 3 less than 16 is written as 16 - 3 and not 3 - 16

Mathematics
1 answer:
Savatey [412]3 years ago
6 0
It is written as 16-3 because it is 16 subtract 3 not 3 subtract 16 because that would come out to  a negative integer. 
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Write the equation of the line perpendicular to -6x+3y=6 that passes through (2,0). Write you answer in slope-intercept form
Svetach [21]

Answer:

The answer is: y - 0 = -1/2(x - 2)

Step-by-step explanation:

Given - an equation in standard form:

-6x + 3y = 6

Solve for y:

Add 6x to both sides:

3y = 6 + 6x

y = 2 + 2x

y = 2x + 2, so the slope is 2.

The perpendicular slope is the negative inverse of 2, which is -1/2.

Point slope form is:

y - y1 = m(x - x1)

Substitute in the numbers from the point (2,0) and the slope -1/2:

y - 0 = -1/2(x - 2)

Taking it to y intercept form:

y = -1/2x + 1

4 0
3 years ago
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GUYS I NEED HELP ASAP!!!<br><br> Help me solve ?
Shalnov [3]

Solution:

$h=\frac{ A-2\pi r^2}{2\pi r }

Given data:

A=2\pi r^2+2\pi r h

Let us determine what is h using given A.

A=2\pi r^2+2\pi r h

Subtract 2\pi r^2 on both sides of the expression.

⇒ A-2\pi r^2=2\pi r^2+2\pi r h-2\pi r^2

⇒ A-2\pi r^2=2\pi r^2-2\pi r^2+2\pi r h

⇒ A-2\pi r^2=2\pi r h

Divide both sides of the expression by 2\pi r.

$\frac{ A-2\pi r^2}{2\pi r }=\frac{2\pi rh }{2\pi r }

$\frac{ A-2\pi r^2}{2\pi r }=h

$h=\frac{ A-2\pi r^2}{2\pi r }

Option C is the correct answer.

Hence $h=\frac{ A-2\pi r^2}{2\pi r }.

8 0
4 years ago
PLEASE HELP ASAP!!
Soloha48 [4]

Answer: Option C.

Step-by-step explanation:

You must use the formula for calculate the volume of a cone, which is shown below:

V_\frac{1}{3}r^2h\pi

Where <em>r</em> is the radius and <em>h </em>is the height.

Based on the figure attached:

r=3in\\h=7in

Substitute these values into the formula for calculate the volume of a cone, then the result is:

V_\frac{1}{3}(3in)^2(7in)\pi

V=65.97in^3≈66in³

5 0
3 years ago
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Ne4ueva [31]

You add 2 to 8 to get 10. I decided on that because that's just what you do for simple addition. ;)

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