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Dovator [93]
3 years ago
11

Write the equation of the line perpendicular to -6x+3y=6 that passes through (2,0). Write you answer in slope-intercept form

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
5 0

Answer:

y = (-1/2)x + 1/2

Step-by-step explanation:

Thank you for sharing the work you've already done!  If we solve -6x+3y=6 for 3y, by adding 6x to both sides, we get 3y = 6x + 6, or (solving for y)

y = 2x + 2.  Compare this to your work.

If this given line -6x+3y=6 has the slope m = 2, then any line perpendicular to it has the slope -1/2, the negative reciprocal of 2.

Now, knowing this new slope and the fact that (2, 0) lines on a line perpendicular to -6x+3y=6, we use the slope-intercept formula, with m = -1/2, y = 0 and x = 2:

That formula, y = mx + b, becomes 0 = -1/2 + b.  Thus, b = 1/2, and the desired equation is

y = (-1/2)x + 1/2.

Svetach [21]3 years ago
4 0

Answer:

The answer is: y - 0 = -1/2(x - 2)

Step-by-step explanation:

Given - an equation in standard form:

-6x + 3y = 6

Solve for y:

Add 6x to both sides:

3y = 6 + 6x

y = 2 + 2x

y = 2x + 2, so the slope is 2.

The perpendicular slope is the negative inverse of 2, which is -1/2.

Point slope form is:

y - y1 = m(x - x1)

Substitute in the numbers from the point (2,0) and the slope -1/2:

y - 0 = -1/2(x - 2)

Taking it to y intercept form:

y = -1/2x + 1

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3 years ago
An expirement consists of rolling two fair number cubes. What is the probability that the sum of the two numbers will be 4? Expr
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Answer:

\dfrac{1}{12}

Step-by-step explanation:

Given:

Two fair number cubes i.e. two dice consisting the numbers 1, 2, 3, 4, 5, 6 on their faces and have equal probability of each number.

The dice are rolled.

To find:

Probability of getting the sum of two numbers as 4.

Solution:

First of all, let us have a look at the total possibilities when two dice are rolled:

([1][1], [1][2], [1][3], [1][4], [1][5], [1][6],

[2][1], [2][2], [2][3], [2][4], [2][5], [2][6],

[3][1], [3][2], [3][3], [3][4], [3][5], [3][6],

[4][1], [4][2], [4][3], [4][4], [4][5], [4][6],

[5][1], [5][2], [5][3], [5][4], [5][5], [5][6],

[6][1], [6][2], [6][3], [6][4], [6][5], [6][6])

These are total 36 possible outcomes.

For getting a sum as 4:

Possible number of favorable cases are 3 (as highlighted in BOLD in above)

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

Required probability is:

\dfrac{3}{36} = \bold{\dfrac{1}{12}}

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