The intersection point of the two lines is (2,1,0).
The respective direction vectors are
L1: <1,2,4>
L2: <4,1,15>
Since the normal vector of the required plane is perpendicular to both direction vectors, the normal vector of the plane is obtained by the cross product of L1 and L2.
i j k
1 2 4
4 1 15
=<30-4, 16-15, 1-8>
=<26, 1, -7>
We know that the plane must pass through (2,1,0), the equation of the plane is
26(x-2)+1(y-1)-7(z-0)=0
simplifying,
26x+y-7z=52+1+0=53
or
26x+y-7z=53
Check:
Put points on L1 in the plane
26(t+2)+(2t+1)-7(4t+0)=53 ok
For L2,
26(4t+2)+(t+1)-7(15t+0)=53 ok
Answer:
Step-by-step explanation:
18 miles..................60 min
18/60= 0.30 miles/ min
10 minutes 0.30*10=3 miles
Remark
I didn't know this was a calculus question. How dumb of me.
f(x + h) - f(x)
==========
x + h - h
50/6 - 51/6 =( -1/6+ h)/h
The h's will disappear when the limit is taken.
answer - 1/6 which is A. If anyone else answers take their answer.
