Write the sum as a product of the GCF and a sum: 39 + 91

1 answer:

zysi [14]3 years ago

4 0

13(3 + 7)

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murzikaleks [220]

$\vec F_3=\langle x,y,z\rangle$ is a force vector such that

$\vec F_1+\vec F_2+\vec F_3=\vec0$

$\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle$

$\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13$

So the missing force is

$\boxed{\vec F_3=\langle-10,-9,-13\rangle}$

8 0

3 years ago

Ugo [173]

Answer:

All real solutions

Step-by-step explanation:

The given graph is a maximum quadratic function.
The solution to the graph is where the graph intersects the x-axis.
We can see from the graph that, the function intersected the x-axis at two different points, hence its discriminant is greater than zero.
Hence the solution of g(x) are two distinct real solutions.
The solutions are not whole numbers because the x-intercepts are not exact.
The solutions are also not all points that lie on g(x)
The first choice is correct.

3 0

3 years ago

denis-greek [22]

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Total watches in an inventory = 1000

Number of shipments sent out = 168, 231, 411

So, Remaining inventory of watches would be :

$1000-(168+231+411)\\\\=1000-810\\\\=190$