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sveta [45]
3 years ago
14

9 less than a number is -1.​

Mathematics
2 answers:
SpyIntel [72]3 years ago
8 0

Answer:

-10

Step-by-step explanation:

oksano4ka [1.4K]3 years ago
7 0

Answer:

-4

hope this helps

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Find the values of X and Y. Write your answers in simplest form.<br> X=__<br> Y=__
uranmaximum [27]
Hope this helps!
Anymore doubt, ask away

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A study was done on the batting averages for two baseball players: Hitmore and Bunter. Data were collected over a period of time
amm1812

Answer:

Both (B) and (C) are correct

Step-by-step explanation:

Explaining in simple terms, The Simpson's paradox simply describes a phenomenon which occurs when observable trends in a relationship, which are obvious during singular evaluation of the variables disappears when each of this relationships are combined. This is what played out when hitmire appears to d well on both of natyraknamd artificial turf when separately compared, but isn't the same when the turf data was combined. Also, performance may actually not be related to the turf as turf may Just be. a lurking variable causing a spurious association in performance.

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3 years ago
Find the area of the shaded region. Round your answer to the nearest tenth.
Alex
Check the picture below on the left-side.

we know the central angle of the "empty" area is 120°, however the legs coming from the center of the circle, namely the radius, are always 6, therefore the legs stemming from the 120° angle, are both 6, making that triangle an isosceles.

now, using the "inscribed angle" theorem, check the picture on the right-side, we know that the inscribed angle there, in red, is 30°, that means the intercepted arc is twice as much, thus 60°, and since arcs get their angle measurement from the central angle they're in, the central angle making up that arc is also 60°, as in the picture.

so, the shaded area is really just the area of that circle's "sector" with 60°, PLUS the area of the circle's "segment" with 120°.

\bf \textit{area of a sector of a circle}\\\\&#10;A_x=\cfrac{\theta \pi r^2}{360}\quad &#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad degrees\\&#10;------\\&#10;r=6\\&#10;\theta =60&#10;\end{cases}\implies A_x=\cfrac{60\cdot \pi \cdot 6^2}{360}\implies \boxed{A_x=6\pi} \\\\&#10;-------------------------------\\\\

\bf \textit{area of a segment of a circle}\\\\&#10;A_y=\cfrac{r^2}{2}\left[\cfrac{\pi \theta }{180}~-~sin(\theta )  \right]&#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad degrees\\&#10;------\\&#10;r=6\\&#10;\theta =120&#10;\end{cases}

\bf A_y=\cfrac{6^2}{2}\left[\cfrac{\pi\cdot 120 }{180}~-~sin(120^o )  \right]&#10;\\\\\\&#10;A_y=18\left[\cfrac{2\pi }{3}~-~\cfrac{\sqrt{3}}{2} \right]\implies \boxed{A_y=12\pi -9\sqrt{3}}\\\\&#10;-------------------------------\\\\&#10;\textit{shaded area}\qquad \stackrel{A_x}{6\pi }~~+~~\stackrel{A_y}{12\pi -9\sqrt{3}}\implies 18\pi -9\sqrt{3}

7 0
3 years ago
What is the area of the hexagon below? 6CM
Brums [2.3K]
365717262cm2
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Evaluate r s + 14s when r= 6 and s= 1/4
arlik [135]
R S + 14(S)        R=6   S=1/4
(6)(1/4) + 14(1/4)
1.5 + 14(1/4)
1.5 + 3.5
5
7 0
3 years ago
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