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4 years ago

The problems are on this screenshot, please answer the questions

Mathematics

2 answers:

rodikova [14]4 years ago

6 0

Answer:

Q1: 48ft

Q2: 14.6

Step-by-step explanation:

Question 1:

Since the two triangles are similar (Angle - Side - Angle):

30/x = 50/80

x= 30(80/50)

=48

Question 2:

sin(55deg) = 12/x

12/sin(55) = x

x=14.6 (3 s.f.)

antoniya [11.8K]4 years ago

5 0

Have a great day because you deserve it ;)

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NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}$

Apply the <u>zero-product property</u> and solve for x:

$\implies x+1=0 \implies x=-1$

$\implies x-5=0 \implies x=5$

Substitute the found values of x into the <u>second equation</u> and solve for y:

$\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}$

$\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}$

Therefore, the solutions are:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

6 0

1 year ago

Read 2 more answers

There are 24 hours in a day. If you want to convert days to hours, should you multiply or divide by 24?

puteri [66]

multiply by 24

eg: 2 days = 2×24 = 48hrs

7 0

2 years ago

140 is what percent of 500?

MAXImum [283]

Answer:

28%

Step-by-step explanation:

5 0

3 years ago

What is the distance between the points (2,10) and (-6, 4) on the coordinate

stellarik [79]

Answer:

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

Therefore distance s=10 units

Step-by-step explanation:

Given points are (2,10) and (-6, 4) on the coordinate plane

To distance between the given points :

The distance formula is $s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ units

Let $(x_1,y_1)$ , $(x_2,y_2)$ be the given points (2,10) and (-6, 4) respectively

Now substituting the values in the distance formula we get

$s=\sqrt{(-6-2)^2+(4-10)^2}$

$=\sqrt{(-8)^2+(-6)^2}$

$=\sqrt{8^2+6^2}$

$=\sqrt{64+36}$

$=\sqrt{100}$

$=10$

Therefore s=10 units

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

5 0

4 years ago

Plz answer i have soo much school work to do thx also brainliest.

m_a_m_a [10]

Answer:

HOPE THIS HELPS

Step-by-step explanation:

Number of students in Mr.Skinner's class who brought lunch from home if there are 20 students in the class=12

Fraction of students who brought lunch from home in Mr. Skinner's class=

Number of students in Ms. Cho's class who brought lunch from home if there are 21 students in the class=14

Fraction of students who brought lunch from home in Ms. Cho's class=

As Siloni is using two 15-section spinners to simulate randomly selecting students from each class and predicting whether they brought lunch from home or will buy lunch in the cafeteria.

Number of Congruent sectors in each Spinner=15

So, if we represent students from Mr. Skinner's class who brought lunch from home in Spinner having 15 congruent Sectors =

So, if we represent students from Mrs. Cho's class who brought lunch from home in Spinner having 15 congruent Sectors =

Mr Skinner class +1 = Mr's Cho's Class

So Ms Cho's class =One more sector of the Skinner-class spinner will represent bringing lunch from home.

Option A which is One more sector of the Skinner-class spinner will represent bringing lunch from home represents Ms Cho's Class.

5 0

3 years ago