Question

If C(x) = 4x^2 - 3, find the following (a) C(0) (b) C (-1) (c) C (-2) (d) C (-3/2)

Answer 1

Step-by-step explanation:

$C(x)=4x^2-3\\\\C(0),\ C(-1),\ C(-2),\ C\left(-\dfrac{3}{2}\right)\\\\\text{Substitute each value}\ \left\{0, -1, -2, -\frac{3}{2}\right\}\ \text{instead}\ C(x):\\\\C(0)=4(0^2)-3=4(0)-3=0-3=-3\\\\C(-1)=4(-1)^2-3=4(1)-3=4-3=1\\\\C(-2)=4(-2)^2-3=4(4)-3=16-3=13\\\\C\left(-\dfrac{3}{2}\right)=4\left(-\dfrac{3}{2}\right)^2-3=4\left(\dfrac{9}{4}\right)-3=9-3=6$