Question

What’s the answer??(SOMEONE PLEASE HELP)

Answer 1

We know that According to Algebra of Real Functions :  

If f and g are two real functions which are defined under the same domain then (f - g)(x) = f(x) - g(x)

Given f(x) = $\frac{2x + 6}{3x}$ and g(x) = $\frac{\sqrt{x} - 8}{3x}$

⇒ (f - g)(x) = f(x) - g(x)

⇒ $(f - g)(x) = \frac{2x + 6}{3x} - \frac{\sqrt{x} - 8}{3x} = \frac{2x + 6 - \sqrt{x} + 8}{3x}$

⇒ $(f - g)(x) = \frac{2x - \sqrt{x} + 14}{3x}$

First Option is the answer

Answer 2

(f - g)(x) = f(x) - g(x)

=  (2x + 6) / 3x - (sqrtx - 8) / 3x

=  [2x + 6 - sqrtx + 8] / 3x

= (2x - sqrtx + 14 ) / 3x    

Its option A