All categories

2 years ago

Hi, can you help me with this probability question?

Mathematics

1 answer:

AURORKA [14]2 years ago

6 0

the probability of getting a black one given that in the first draw we got a black one is P = 1/2 = 0.5

<h3>How to find the probability?</h3>

We will assume that all the beads have the same probability of being randomly selected.

Then the probability of picking a black bead is equal to the quotient between the number of black beads and the total number of beads.

Originally, there are 4 black ones and 3 red ones ( a total of 7).

We want to get the probability of getting a black one given that in the first draw we got a black one.

If in the first draw we got a black one, then now there are 3 blacks and 3 reds (a total of 6 beads).

So the probability of getting another black one is:

P = 3/6 = 1/2 = 0.5

If you want to learn more about probability:

brainly.com/question/251701

#SPJ1

You might be interested in

Department started out with 100 pencils and 200 pens during the lat quarter of this year they lost 4% of the pens and 2% of the

o-na [289]

Answer:

The remaining number of the pencil = 98

The remaining number of the pens = 192

Step-by-step explanation:

Here, according to the question:

The number of pencils at the starting at the quarter = 100

The percentage of the lost pencil over the year = 2%

Now, calculating the lost pencil, we get:

2% of 100 = $\frac{2}{100} \times 100 = 2$

⇒The number of lost pencil over the year = 2

So,Number of remaining Pencil = Total pencil - Number of pencil lost

= 100 - 2 = 98

The number of pens at the starting at the quarter = 200

The percentage of the lost pens over the year = 4%

Now, calculating the lost pens, we get:

4% of 200 = $\frac{4}{100} \times 200 = 8$

⇒The number of lost pens over the year = 8

So,Number of remaining Pens = Total pens - Number of pens lost

= 200 - 8 = 192

Hence, the remaining number of the pencil = 98

And and the remaining number of the pens at the end of the year = 192

6 0

3 years ago

write a division equation to represent the repeated subtraction 32 take away 8 is 24 24 take away 8 is16 16 take away 8 is 8/8 t

grin007 [14]

What this setup essentially represents is “How many 8s can we take away from 32 before hitting 0?” Which in turn can be reframed as “How many 8s fit into 32?” This can be captured in the expression 32 / 8. As we can see from the problem, we can take away 4 8’s before hitting 0, so that gives us the equation 32 / 8 = 4

4 0

3 years ago

Help I don't know how to do this

yan [13]

The answer would be A

5 0

3 years ago

HELP PLEASE DUE IN 3 MINUTES

miv72 [106K]

Answer:

im pretty sure its 6 hope i helped

8 0

3 years ago

A line passes through point (-6, -8) and has a slope of

vlada-n [284]

Agile asertation anigaa man aqaani sa lo samaayo

8 0

3 years ago