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Nata [24]
3 years ago
9

Pete roller skates with a constant speed of 16km/h.how far can he travel in 2 1/2 hours?

Mathematics
1 answer:
WINSTONCH [101]3 years ago
5 0

\frac{6}{x}  =  \frac{1}{2 \frac{1}{2} }
use butterfly method:
(6)(2 1/2) = x
15 = x
x = 15
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Steinmetz furniture buys 2 products for resale: big shelves (B) and medium shelves (M). Each big shelf costs $100 and requires 1
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3 years ago
How many $10 bills are the same as ten $ 1 bill?
Schach [20]
10 they have 10 dollar bill
7 0
3 years ago
Read 2 more answers
A bowl contains 80 M&M candies if 15 of the candies are orange what fraction of the candies
Angelina_Jolie [31]
13/16 are not orange

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6 0
3 years ago
Solve using the quadratic formula:<br> 3x=2x^2-2
Tomtit [17]

Answer:

x=2\\x=-\frac{1}{2}

Step-by-step explanation:

1) Move terms to the left side.

3x=2x^{2} -2\\3x-(2x^{2}-2)=0

2) Distribute.

3x-(2x^{2} -2)=0\\3x-2x^{2} +2=0

3) Rearrange terms.

3x-2x^{2} +2=0\\-2x^{2} +3x+2=0

4) Common factor.

-2x^{2} +3x+2=0\\-(2x^{2} -3x-2)=0

5) Divide both sides of the equation by the same term.

-(2x^{2} -3x-2)=0\\2x^{2} -3x-2=0

6) Use the quadratic formula.

x=\frac{-b+\sqrt{b^{2}-4ac } }{2a}

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

2x^{2} -3x-2=0\\a=2\\b=-3\\c=-2

x=\frac{-(-3)+\sqrt{(-3)^{2} -4*2(-2)} }{2*2}

7) Simplify.

Evaluate the exponent

x=\frac{3+\sqrt{(-3)^{2}-4*2(-2) } }{2*2}

x=\frac{3+\sqrt{9-4*2(-2)} }{2*2}

Multiply the numbers

x=\frac{3+\sqrt{9-4*2(-2)} }{2*2}

x=\frac{3+\sqrt{9+16} }{2*2}

Add the numbers

x=\frac{3+\sqrt{9+16} }{2*2}

x=\frac{3+\sqrt{25} }{2*2}

Evaluate the square root

x=\frac{3+\sqrt{25} }{2*2} \\x=\frac{3+5}{2*2}

Multiply the numbers

x=\frac{3+5}{2*2}

x=\frac{3+5}{4}

8) Seperate the equations.

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.

x=\frac{3+5}{4}

x=\frac{3-5}{4}

9) Solve.

Rearrange and isolate the variable to find each solution.

x=2\\x=-\frac{1}{2}

7 0
3 years ago
Solve for 2cos^2theta + 13costheta = -6. theta is &gt;= 0 and &lt; 360 degrees
LiRa [457]
\\ 2cos^2 \theta+13cos \theta=-6 \\ 2cos^2 \theta+13cos \theta+6=0 \\ 2cos^2 \theta+12cos \theta+1cos \theta+6=0 \\ 2cos \theta(cos \theta+6)+1(cos \theta+6)=0  \\ (2cos\theta +1)(cos\theta+6)=0 \\

cos\theta+6=0 \\ cos\theta=-6 \\    \\ cos(x)=|a| \leq 1 \\ |-6| \geq 1 \\  \\


2cos \theta+1=0 \\ 2cos \theta=-1 \\ cos \theta=- \frac{1}{2} \\ \theta= \frac{ 2\pi }{3} +2 \pi k~~~k \in Z \\  \\ 0 \leq \theta \ \textless \ 360^{а}  \\ 0 \leq \theta \ \textless  \ 2 \pi  \\  \theta = \frac{2 \pi }{3}  \\ \theta = \frac{2 \pi }{3} ,  \frac{4 \pi }{3}


7 0
3 years ago
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