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BaLLatris [955]
3 years ago
5

How many $10 bills are the same as ten $ 1 bill?

Mathematics
2 answers:
Schach [20]3 years ago
7 0
10 they have 10 dollar bill
AURORKA [14]3 years ago
4 0

Answer:

10 * $1 = $ 10

$10 / 10 = 1

one 10$ bill

pretty simple

Step-by-step explanation:

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A oreos says that now it contains 20% more. Originally, it came with 19.5 ounces of oreos . How much oreos does the box come
Lera25 [3.4K]

Answer:

23.4 oz

Step-by-step explanation:

5 0
3 years ago
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10(2^×) + 7(3^×) = 6^× + 70​
Mkey [24]

Answer:

x = 2.81 and 2.096

Step-by-step explanation:

Given the expression

10(2^x) + 7(3^x) = 6^x + 70​

This can also be expressed as;

10(2^x) + 7(3^x) = (2*3)^x + 70

10(2^x) + 7(3^x) = 2^x*3^x + 70

Let a  = 2^x and b = 3^x

10a + 7b = ab + 70

10a + 7b - ab = 70

10a-ab + 7b - 70 = 0

a(10-b)+7(b-10) = 0

a(10-b)-7(10-b) = 0

a-7 = 0 and 10-b = 0

a = 7 and b = 10

Since a = 2^x

7 = 2^x

log 7 = log2^x

log7 = xlog2

x = log7/log2

x = 2.81

Similarly

10 = 3^x

log 10 = log 3^x

log 10 = xlog3

x = log 10/log 3

x = 1/0.4771

x = 2.096

Hence the values of x that satisfies the equation are 2.81 and 2.096

8 0
3 years ago
F(x) = x+3 help<br> Please
schepotkina [342]

Answer:

x=-3

Step-by-step explanation:

F(x) just means X.

0=x+3

0-3=x+3-3

-3=x

3 0
3 years ago
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Prove that 1/sec0-tan0= sec0+tan0
Leviafan [203]

Answer:

Step-by-step explanation:

\text{LHS}=\frac{1}{\sec \theta-\tan \theta}\\=\frac{\sec \theta+\tan \theta}{(\sec \theta-\tan \theta)(\sec \theta+\tan \theta)}\\=\frac{\sec \theta+\tan \theta}{\sec^{2} \theta-\tan^{2} \theta}\\=\frac{\sec \theta+\tan \theta}{1}\\=\sec \theta+\tan \theta\\=\text{RHS}

7 0
2 years ago
Find the area of a rhombus with side length 6 and an interior angle with measure $120^\circ$.
Serhud [2]

Answer:

The area of a rhombus is 18\sqrt{3} square units.

Step-by-step explanation:

Side length of rhombus = 6 units.

Interior angle of rhombus = 120°

another Interior angle of rhombus = 180°-120° = 60°.

Draw an altitude.

In a right angled triangle

\sin \theta=\frac{opposite}{hypotenuse}

\sin (60)=\frac{h}{6}

\frac{\sqrt{3}}{2}=\frac{h}{6}

Multiply both sides by 6.

3\sqrt{3}=h

The height of the rhombus is 3\sqrt{3}.

Area of a rhombus is

Area=base\times height

Area=6\times 3\sqrt{3}

Area=18\sqrt{3}

Therefore, the area of a rhombus is 18\sqrt{3} square units.

8 0
3 years ago
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