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worty [1.4K]
3 years ago
5

10 Renee buys 5 kg of sweets to sell.

Mathematics
1 answer:
alexgriva [62]3 years ago
4 0

Answer:

The profit is 30%

Step-by-step explanation:

Please kindly see the attached file for more explanation

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All real numbers between −14 and 14 inclusive
Vladimir79 [104]

Answer:

-13, -12, -11, -10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13

6 0
3 years ago
Read 2 more answers
Please help I really need your help
Amanda [17]

Answer:

1.  1200 \ kg/m^3

2.

a)

35 cm = 0.35 meters

11 dm = 1.1 meters

15 mm = 0.015 meters

b)

Volume = 0.005775 cubic meters

Mass = 15.5925 kilograms

Step-by-step explanation:

1.

We know

Density = Mass/Volume

Given

Mass = 90 kg

Volume = 0.075 cubic meters

The SI unit for density is kilograms per cubic meters. Our dimensions are just that, so we just need to plug in the numbers into the formula and get our answer. Shown below:

Density = \frac{90}{0.075}=1200 \ kg/m^3

The Density of asphalt block = 1200 \ kg/m^3

2.

a)

We need to express 35cm, 11dm, and 15mm in meters

We know

100 cm = 1 meters, so

35 cm = 35/100 = 0.35 meters

We know 1 dm = 0.1 meters, so

11 dm * 0.1 = 1.1 meters

We know, 1mm = 0.001 meters, so

15 mm * 0.001 = 0.015 meters

b)

Volume of the Slab is length * width * height, in meters, that would be:

Volume = 0.35 * 1.1 * 0.015 = 0.005775 cubic meters

THe mass would be found by the formula:

Density = Mass/Volume

2700 = Mass/0.005775

Mass = 0.005775 * 2700 =  15.5925 kilograms

5 0
3 years ago
The slope of a line is -4 and Y negative intercept is -3 what is the equation of the line written in slope intercept form
lord [1]

Answer:

y = mx + c

m = -4

at y intercept x = 0

(x,y) =(0,-3)

-3 = -4(0) + c

c = -3

therefore the answer is y = -4x + c

8 0
2 years ago
Which function represents the graph below?
zimovet [89]

Answer:

The inequalities all need to be of the form a < x ≤ b. i think that is it

3 0
2 years ago
Suppose brine containing 0.2 kg of salt per liter runs into a tank initially filled with 500 L of water containing 5 kg of salt.
Oliga [24]

Answer:

(a) 0.288 kg/liter

(b) 0.061408 kg/liter

Step-by-step explanation:

(a) The mass of salt entering the tank per minute, x = 0.2 kg/L × 5 L/minute = 1 kg/minute

The mass of salt exiting the tank per minute = 5 × (5 + x)/500

The increase per minute, Δ/dt, in the mass of salt in the tank is given as follows;

Δ/dt = x - 5 × (5 + x)/500

The increase, in mass, Δ, after an increase in time, dt, is therefore;

Δ = (x - 5 × (5 + x)/500)·dt

Integrating with a graphing calculator, with limits 0, 10, gives;

Δ = (99·x - 5)/10

Substituting x = 1 gives

(99 × 1 - 5)/10 = 9.4 kg

The concentration of the salt and water in the tank after 10 minutes = (Initial mass of salt in the tank + Increase in the mass of the salt in the tank)/(Volume of the tank)

∴ The concentration of the salt and water in the tank after 10 minutes =  (5 + 9.4)/500 = (14.4)/500 = 0.288

The concentration of the salt and water in the tank after 10 minutes = 0.288 kg/liter

(b) With the added leak, we now have;

Δ/dt = x - 6 × (14.4 + x)/500

Δ = x - 6 × (14.4 + x)/500·dt

Integrating with a graphing calculator, with limits 0, 20, gives;

Δ = 19.76·x -3.456 = 16.304

Where x = 1

The increase in mass after an increase in = 16.304 kg

The total mass = 16.304 + 14.4 = 30.704 kg

The concentration of the salt in the tank then becomes;

Concentration = 30.704/500 = 0.061408 kg/liter.

6 0
3 years ago
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