You would cross multiply 53 times 5 and divide by 1
<span>1/4+3/4+3 3/4+1 1/2+5 1/2, which is 11 3/4 ounces.</span>
Log₄20-log₄ 45+log₄144=
log₄(20/45)+log₄144= (log_a b- log_a c=log_a (b/c) )
log₄[(20*144)/45]= (log_a b +log_a c=log_a (b*c) )
log₄(2880/45)=
log₄(64)=n ⇔ 4^n=64 (log_a x=n ⇔ a^n=x)
4^n=4³ ⇒n=3 (64=4*4*4=4³)
Answer: log₄20-log₄ 45+log₄144=3
Add up the fractional amounts and divide them by however many amounts there are..........
eg.
Step 1:Add the fractions
1/6 + 5/8 +3/4
(find the LCD)
1/6 + 5/8 + 3/4 = 4/24 + 15/24 + 18/24 = 37/24
Step 2: Divide the sum by the number of numbers in the set
37/24 ÷ 3= 37/24 ÷ 3/1= 37/24 X 1/3= 37/72
<span>So the mean (average) is 37/72</span>
I set it in a big problem. Since you know that all the angles of a triable add up to 180,
m<a + m<b + m<c = 180, plug in equations/values
(36) + (3x+12) + (3x+18) = 180, subtract 36
3x+12 + 3x+18 = 144, combine like terms,
6x+30 = 144, subtract 30,
6x=114, divide by 6,
x=19. Plug in X to the equations for m<b and m<c
