Ask question

Ask question

All categories

3 years ago

8

Devin started the work shown to solve for the unknown angle measures. 8x – 1 + 9x – 6 = 180 17x – 7 = 180 17x = 187 What are the

measures of angles Q and R?

2 answers:

makvit [3.9K]3 years ago

6 0

Answer:

$m$

$m$

Step-by-step explanation:

we have that

$m$

$m$

$m$ ------> by supplementary angles

Substitute the values and solve for x

$8x-1+9x-6=180\°$

$17x-7=180\°$

$17x=187\°$

$x=11\°$

Find the value of angle R

$m$

Find the value of angle Q

$m$

nadezda [96]3 years ago

4 0

Answer:

93 and 87

Step-by-step explanation:

You might be interested in

4y =<br> = -x + 16 and y=x+9

uranmaximum [27]

Step-by-step explanation:

O sea que nada más la tarea pregúntale la pulsera o es algo que se siente

4 0

3 years ago

The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation

Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

Sample size: n = 20
Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}$

This gives

$P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}$

$P(x = 11) = 0.0011$

Express as percentage

$P(x = 11) = 0.11\%$

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}$

This gives

$P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0$

$P(x = 20) = 0.0388$

Express as percentage

$P(x = 20) = 3.88\%$

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

$\mu = np$

So, we have:

$\mu = 20 \times 85\%$

$\mu = 17$

The standard deviation is calculated as:

$\sigma = np(1 - p)$

So, we have:

$\sigma = 20 \times 85\% \times (1 - 85\%)$

$\sigma = 20 \times 0.85 \times 0.15$

$\sigma = 2.55$

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

8 0

3 years ago

Can u help me with 2/3/4 I didn't understand

katovenus [111]

You have to fraw sticks as the 10's for example #2 prtend thise are the sticks.(I)
IIII 4 tens in 42 the circles as ones O O SO,IIII00

8 0

3 years ago

Read 2 more answers

State the restrictions on the domain.

mihalych1998 [28]

we know that, denominator ≠ 0

16y² ≠ 0

y ≠ 0 is excluded value.

8 0

2 years ago

Select the correct answer.

zhannawk [14.2K]

You have a good day and good luck on that question

8 0

3 years ago