John will pay $8.68 for the combined cost of 1 pound of banana and 1 pound of cherries.
Let: b=cost of banana per pound and c=cost of cherries per pound
Equation 1: For 3 pounds of cherries and 2 pounds of bananas, John pays a total of $24.95.
3c + 2b =$24.95
Equation 2: The cost of bananas is $6.50 less than a pound of cherries.
b= c - $6.50
We can substitute the second equation into the first one to solve for the cost of cherries per pound.
3c + (2)(c-$6.50)= $24.95
3c + 2c -$13.00 = $24.95
5c = $24.95 + $13.00
c = $7.59
Substituting the value of c to the second equation to solve for b.
b= $7.59 - $6.50 = $1.09
The combined cost of 1 pound of banana and 1 pound of cherries is $1.09 + $7.59 or $8.68.
For more information regarding the system of equations, please refer to brainly.com/question/25976025.
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Answer:
3/4
Step-by-step explanation:
A: students present
B: students on time
P(all students present and on time) = P(A and B) = 3/10
P(all students present) = P(A) = 2/5
P(A and B) = P(A).P(B|A) where P(B|A) is the probability of everyone being on time given that everyone is present
So P(B|A) = P(A and B) /P(A) = 3/10 ÷ 2/5 = 3/10 * 5/2 = 15/20 which can be reduced to 3/4 by dividing numerator and denominator by 5
It would be B. 9*4=36. 25% is 1/4
Answer:
B is correct. Your starting amount is 210$ And you're taking away 15$ each time she uses the club,x.
Step-by-step explanation:
Answer:
The linear function model the situation is b = 210 - 15x .
Option (B) is correct .
Step-by-step explanation:
Let us assume that the number of times giselle uses the club be x .
As given
giselle pays $210 in advance on her account at the athletic club.
Each time she uses the club,$15 is deducted from the account.
Let suppose that the money left after giselle uses the club x times is b .
Than the equation becomes
Money left = Amount pay in advance - Deducted amount × Number of times giselle uses the club .
Put all the values in the above
b = 210 - 15 × x
b = 210 - 15x
Therefore the linear function model the situation is b = 210 - 15x .
Option (B) is correct .
