Complete Question
A dog weighs 2 pounds less than 3 times the weight of a cat. The dog weighs twenty two more pounds than the cat.
Write and solve an equation to find the weights of the cat and the dog.
Answer:
Weight of cat = x = 12 pounds
Weight of Dog = y = 34 pounds
Step-by-step explanation:
Let's represent:
Weight of cat = x
Weight of Dog = y
A dog weighs 2 pounds less than 3 times the weight of a cat.
y = 3x - 2........ Equation 1
The dog weighs twenty two more pounds than the cat
y = x + 22....... Equation 2
The equation is given as:
y = y
3x - 2 = x + 22
Collect like terms
3x - x = 22 + 2
2x = 24
x = 24/2
x = 12 pounds
Solving for y using any of the equations:
y = 3x - 2
y = 3 × 12 - 2
y = 36 - 2
y = 34 pounds
Therefore:
Weight of cat = x = 12 pounds
Weight of Dog = y = 34 pounds
hi,
Express the ratios in fractional form, that is
= ( cross- multiply )
y + 3 = k(y + 5) ← distribute
y + 3 = ky + 5k ( subtract ky from both sides )
y - ky + 3 = 5k ( subtract 3 from both sides )
y - ky = 5k - 3 ← factor out y from each term on the left side
y(1 - k) = 5k - 3 ← divide both sides by (1 - k)
y = 5k- 3
____
1 - k
Answer:
A: (3^2)*2
B: (2^3)*3
C: 2*19
D: (3^2)*9
Step-by-step explanation:
We have:
A) 18= 3*3*2= (3^2)*2
B) 24=2*2*2*3=(2^3)*3
C) 38 = 2*19
D) 81 =3*3*9=(3^2)*9
Since PQ bisects both MO and NO, it should be exactly 1/2 of the far parallel side.
PQ = 1/2 MN
PQ = 1/2×14.4 = 7.2
