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amid [387]
3 years ago
11

2. Order 3.3,3.19,3 1/5,3 1/3.

Mathematics
1 answer:
cricket20 [7]3 years ago
8 0
2.
3\frac15=3.2\\ 3\frac13=3.33333...

3.19, \ \ \ 3\frac15, \ \ \ 3.3, \ \ \ 3\frac13

3.
20\%\cdot1500\$=0.2\cdot1500\$=300\$

4.
\frac{600g}{3kg}=\frac{600g}{3000g}=\frac{600g}{5\cdot600g}=\frac15
This fraction is \frac15

5. 
10^3+10^2+10+1=1000+100+10+1=1111

6. 6.7\cdot5\$=33.5\$

7. 
180-40\%\cdot180=180-0.4\cdot180=180-72=108

8.
9^2-4\cdot9=81-36=45

9.
from 8.45am to 12.45pm - 4 hours
\$15\cdot4=\$60
I earn \$60

10.
48 minutes = 1 hour - 12 min
21.15 - 1 hour = 20.15
20.15 + 12 min = 20.27

11. 
34.1^oC-27.6^oC=6.5^oC

12. 
8\frac14 \ h= 8h \ 15min
10.30pm+8h = 6.30am\\ 6.30am+15min  = \boxed{6.45am}
I get up at 6.45am

13.
12\cdot108=1296

14.
\overline{x}=\frac{8.2+9.4+3.5+2.9}4=\frac{24}4=6

15.
48\cdot26=1248 \ \ \ - \ \ \ total \ amount \ of \ lolipops \ in \ 48 \ bags\\ 1248\cdot20g=24960g = \boxed{24.96kg} \ \ \ - \ \ \  total \ weight \ of \ the \  48  \ bags\\

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4 0
3 years ago
Kenyon ran for 8 miles each week while training. Here is his record of the number of miles he ran.
diamong [38]

Step-by-step explanation:

Let x be the miles Kenyon ran on tuesday

Let y be the miles Kenyon ran on thursday

Given,

Mon + Tues + Wed + Thu = 8mi

1.2 + x + 1.6 + y = 8 \\ 2.8 + x + y = 8 \\ x + y = 8 - 2.8 \\ x + y = 5.2

also given,

y = x + 0.4 \\  - x + y = 0.4

Now we have x + y = 5.2 as equation 1 and -x + y = 0.4 as equation 2

Using equation 1,

x + y = 5.2 \\ x = 5.2 - y

Substitute this equation into equation 2.

- (5.2 - y) + y = 0.4 \\  - 5.2 + y + y = 0.4 \\  - 5.2 + 2y = 0.4 \\ 2y = 0.4 + 5.2 \\ 2y = 5.6 \\ y = 5.6 \div 2 \\  = 2.8mi

Substitute y = 2.8 into equation 1.

x + 2.8 = 5.2 \\ x = 5.2 - 2.8 \\  = 2.4mi

Therefore Kenyon ran 2.4 miles on tuesday, and ran 2.8 miles on thursday.

8 0
2 years ago
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