Given:
The two way table.
To find:
The conditional probability of P(Drive to school | Senior).
Solution:
The conditional probability is defined as:

Using this formula, we get
...(i)
From the given two way table, we get
Drive to school and senior = 25
Senior = 25+5+5
= 35
Total = 2+25+3+13+20+2+25+5+5
= 100
Now,


Substituting these values in (i), we get




Therefore, the required conditional probability is 0.71.
Answer:
The Taylor series of f(x) around the point a, can be written as:

Here we have:
f(x) = 4*cos(x)
a = 7*pi
then, let's calculate each part:
f(a) = 4*cos(7*pi) = -4
df/dx = -4*sin(x)
(df/dx)(a) = -4*sin(7*pi) = 0
(d^2f)/(dx^2) = -4*cos(x)
(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4
Here we already can see two things:
the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.
so we only will work with the even powers of the series:
f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....
So we can write it as:
f(x) = ∑fₙ
Such that the n-th term can written as:

Answer: Well you’re solving for “x,” so you’ll need to isolate this variable. This means we need to “get rid of” the fraction 2/3 that is attached to it. The faction is attached by the operation multiplication, so to remove it we must divide it on both sides. And division with fractions requires the reciprocal. (Try watching an explanation if you’re confused on why division requires reciprocals).
To find a perimeter, add all sides together:
9) 12 + 12 + 8 + 8 = 20 + 20 = 40 in
10) 3 + 3 + 3 + 3 = 6 + 6 = 12 cm
To find area, multiply length and width, or base and height:
11) 3 x 6 = 18
12) 10 x 30 = 300 ft
13) 12 x 12 = 144 cm
14) 7 x 4 = 28 m
15)
Perimeter: 2(2) + 2(16) = 4 + 32 = 36
Area: 1 x 16 = 16
hope this helps