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Answer:
The length of the patio is 32 ft and the width is 13 ft
Step-by-step explanation:
see the attached figure to better understand the problem
Let
L ----> the length of his patio
W ---> the width of his patio
we know that
----> equation A
----> equation B
substitute equation B in equation A and solve for W
Find the value of L
---->
therefore
The length of the patio is 32 ft and the width is 13 ft
Answer:
132 mm^2
Step-by-step explanation:
The line added to the figure in the attachment shows it can be divided into two figures whose area is easily calculated.
1. A parallelogram of base length 20 mm and height 4 mm:
A = bh = (20 mm)(4 mm) = 80 mm^2
2. A trapezoid with bases 32 mm and 20 mm, and height 2 mm:
A = (1/2)(b1 +b2)h = (1/2)(32 mm +20 mm)(2 mm) = 52 mm^2
The total area of the figure is then ...
80 mm^2 +52 mm^2 = 132 mm^2
