Answer:
5. f(x) = -2x² + 3x
f(-3) = -2(-3)² + 3(-3) = -27
f(2) = -2(2)² + 3(2) = -2
f(-a) = -2(-a)² + 3(-a) = -2a² - 3a
-f(a) = -[-2a² + 3a] = 2a² - 3a
f(a + h) = -2(a + h)² + 3(a + h) = -2(a² + 2ah + h²) + 3a + 3h = -2a² - 4ah - 2h² + 3a + 3h
6. f(x) = 2|3x - 1|
f(-3) = 2|3(-3) - 1| = 2*10 = 20
f(2) = 2|3(2) - 1| = 2*5 = 10
f(-a) = 2|3(-a) - 1| = 2|-3a - 1|
-f(a) = -(2|3a - 1|) = -2|3a - 1|
f(a + h) = 2|3(a + h) - 1| = 2|3a + 3h - 1|
Answer:
<em>Proof below</em>
Step-by-step explanation:
<u>Exponential Grow Model</u>
The equation to model some time dependant event as an exponential is
Where Ao is the initial value, k is a constant and t is the time. With the value of Ao and k, we can compute the value of A for any time
We are required to find the time when the population being modeled doubles from Ao to 2 Ao. We need to solve the equation
Simplifying by Ao
Taking logarithms in both sides
By properties of logarithms and since lne=1
Solving for t
Hence proven
Answer:
It's 143
Step-by-step explanation:
Your welcome have a good day!!!
It should be about 214 monthly for tuition for a year
Answer:
- g(-x) = 70 +3x
- -g(x) = -70 +3x
- -g(-x) = -70 -3x
Step-by-step explanation:
Put the minus signs where the problem statement tells you. As with any function, the argument replaces the variable in the function definition. That is, for g(-x), you put (-x) where x is in the definition of the function.
g(-x) = 70 -3(-x) = 70 +3x
-g(x) = -(70 -3x) = -70 +3x
-g(-x) = -(70 -3(-x)) = -70 -3x
