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lyudmila [28]
3 years ago
6

Find 5% less than rupees 180​

Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0

Answer:

5% less of 180, or 95% of 180

Step-by-step explanation:

FInd 10% of 180, 18, multiply 18 by 9.

18 x 9 = 162, find half of 18 which is 9.

Add to 162.

162 + 9 = 171.

Therefore,

5% less of 180 is 171.

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The equation v/2 -21=-15 is solved in several steps below.
Arada [10]

Answer:

V/2 - 21 = -15

V/2 - 21 + 21 = -15 + 21

V/2 + 0 = 6

V/2 * 2 = 6 * 2

V = 12

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3 years ago
What is a fraction strips
MrRa [10]

Fraction strips are rectangular pieces (electronic or copied on paper strips) to represent different parts of the same whole. They can be cut apart and manipulated to see how various parts can be added together to make the whole or compare different fractional amounts for equivalency

6 0
3 years ago
Read 2 more answers
8 to the power 1/6 times 2 to the power x equals 32 to the power 1/2
Elza [17]

The exact value of x is 2.

<h3>What is linear equation?</h3>

A linear equation is a first-order (linear) term plus a constant in the algebraic form y=mx+b, where m is the slope and b is the y-intercept. This is sometimes referred to as a "linear equation with two variables," where y and x are the variables.

8⁽¹/⁶⁾ x 2ˣ = 32⁽¹/²⁾

32⁽¹/²⁾ = 2⁵⁽¹/²⁾

32⁽¹/²⁾ = 2⁽⁵/²⁾

8⁽¹/⁶⁾ = 2³⁽¹/⁶⁾

8⁽¹/⁶⁾ = 2⁽¹/²⁾

8⁽¹/⁶⁾ x 2ˣ = 2⁽¹/²⁾ x 2ˣ

= 2⁽¹/²⁾+ˣ  

= 2⁽¹/²+ˣ⁾

since 8⁽¹/⁶⁾ x 2ˣ  = 32⁽¹/²⁾

= 2⁽⁵/²⁾

2⁽¹/²+ˣ⁾ = 2⁽⁵/²⁾

equate the powers

1/2+ x = 5/2

subtract 1/2 from both sides

x = 5/2 - 1/2

x = (5-1)/2

x = 4/2

x= 2

Therefore, x = 2 is the exact value of x.

To know more about linear equation, visit:

brainly.com/question/11897796

#SPJ9

4 0
1 year ago
The length of a rectangle is 3 meters longer than the width. if the area is 36 square​ meters, find the​ rectangle's dimensions.
kompoz [17]
Here you are. you can see my explication.
have fun

8 0
3 years ago
How do you simplify (9x^8 y^3)^1/2
kondaur [170]
\left(9x^8y^3\right)^\frac{1}{2}=\left(3^2x^8y^3\right)^\frac{1}{2}=\left(3^2\right)^\frac{1}{2}\cdot\left(x^8\right)^\frac{1}{2}\cdot\left(y^3\right)^\frac{1}{2}\\\\=3^{2\cdot\frac{1}{2}}\cdot x^{8\cdot\frac{1}{2}}\cdot y^{3\cdot\frac{1}{2}}=3^1\cdot x^4\cdot y^\frac{3}{2}=3x^4\cdot y^{1\frac{1}{2}}\\\\=3x^4\cdot y^{1+\frac{1}{2}}=3x^4\cdot y^1\cdot y^\frac{1}{2}=3x^4y\sqrt{y}
7 0
3 years ago
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