All categories

2 years ago

What is the GCF of 55 and 100?

Mathematics

2 answers:

oksian1 [2.3K]2 years ago

5 0

Common factors are . . . 1 & 5 . . . do the greatest common factor is 5

ValentinkaMS [17]2 years ago

3 0

The GCF is the Greatest Common Factor, which means that it is the highest number that divides exactly into two (or more) numbers, in this case 55 and 100. You start off by listing all of the factors of both numbers. When you have finished, you find the highest factor that goes into them both, and that is the answer.

1, 5, 11, 55.
1, 2, 4, 5, 10, 20, 25, 50, 100.

As you can see, the highest number that goes into them both is 5. Therefore, the GCF of 55 and 100 is 5.

You might be interested in

How are corresponding angles of two similar figures related

seraphim [82]

Answer:

the corresponding angles are equal in similar figures.

Step-by-step explanation:

When two figures are similar then the corresponding angles of the two figures are equal. the side of the figures are in proportional.

for example, when triangle ABC is similar to triangle DEF

then the corresponding angles are equal

<A=<D

<B=<E

<C=<F

so the corresponding angles are equal in similar figures.

6 0

3 years ago

What is the perimeter of the parallelogram???

enot [183]

Answer: 22

explanation: the easiest way is to separate one of the diagonals into a triangle and use the pythagorean theorem.
a^2 + b^2 = c^2
4^2 + 3^3 = c^2
16 + 9 = c^2
25 = c^2
5 = c
you now know that both of the diagonals have a length of 5.
by counting the units on the two straight, you know that their length is 6.
6 + 6 + 5 + 5 = 22

8 0

3 years ago

Roulette is a casino game that involves spinning a ball on a wheel that is marked with numbered squares that are red, black, or

a_sh-v [17]

Answer:

.6315 or 63.15%

Step-by-step explanation:

not sure if the question is trying to be tricky, but there are 0 and 00 which makes a total of 38 numbers on the wheel (and they are less than 12)

24/38 = .6315

6 0

2 years ago

What is the total surface area

Stels [109]

We have two right triangles and three different rectangles.

The formula of an area of a right triangle:

$A_T=\dfrac{1}{2}l_1l_2$

l₁, l₂ - legs

We have l₁ = 20cm and l₂ = 21cm. Substitute:

$A_T=\dfrac{1}{2}(20)(21)=(10)(21)=210\ cm^2$

The formula of an area of a rectangle:

$A_R=lw$

l - length

w - width

We have:

rectangle #1: l = 22cm, w = 29cm

$A_{R1}=(22)(29)=638\ cm^2$

rectangle #2: l = 22cm, w = 21cm

$A_{R2}=(22)(21)=462\ cm^2$

rectangle #3: l = 22cm, w = 20cm

$A_{R3}=(22)(20)=440\ cm^2$

The total Surface Area of the triangular prism:

$S.A.=2A_T+A_{R1}+A_{R2}+A_{R3}\\\\S.A.=2\cdot210+638+462+440=1960\ cm^2$

3 0

2 years ago

What is the answer to 1.1x + 1.2x - 5.4 = -10

lord [1]

1.1x+1.2x-5.4=-10

11/10x+12/10x-54/10=10

11x/2.5+2^2-1*3/5x-3^3/5=-10

(11x)+2(2*3x)+2(-3^3)/2*5=-10

11x+2(6x)+2(-27)/2*5=-10

11x+2*6x-2*27/2*5=-10

11x+12x-54/2*5=-10

23x-54/2*5=-10

23x-54=-100

23x=-46

23x/23=-46/23

x=-2*23/23

x=-2

8 0

3 years ago

Read 2 more answers